Home
Class 11
MATHS
The ends of a line segment are P(1, 3) ...

The ends of a line segment are `P(1, 3) and Q(1,1)`, R is a point on the line segment PQ such that `PR : QR=1:lambda`.If R is an interior point of the parabola `y^2=4x` then

A

(0, 1)

B

(-3/5, 1)

C

(1/2, 3/5)

D

none of these

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem step by step, we will first find the coordinates of point R on the line segment PQ and then determine the conditions under which R is an interior point of the parabola \(y^2 = 4x\). ### Step 1: Determine the coordinates of point R Given the points \(P(1, 3)\) and \(Q(1, 1)\), we need to find the coordinates of point R such that the ratio \(PR : QR = 1 : \lambda\). Let the coordinates of point R be \((1, y)\) since both P and Q have the same x-coordinate. Using the section formula, the coordinates of R can be expressed as: \[ R = \left(\frac{m x_2 + n x_1}{m+n}, \frac{m y_2 + n y_1}{m+n}\right) \] where \(m = 1\), \(n = \lambda\), \(P(1, 3)\) is \((x_1, y_1)\), and \(Q(1, 1)\) is \((x_2, y_2)\). Substituting the values: \[ R = \left(1, \frac{1 \cdot 1 + \lambda \cdot 3}{1 + \lambda}\right) = \left(1, \frac{3\lambda + 1}{\lambda + 1}\right) \] ### Step 2: Determine the condition for R to be an interior point of the parabola For R to be an interior point of the parabola \(y^2 = 4x\), the point must satisfy the inequality: \[ y^2 < 4x \] Substituting the coordinates of R into the inequality: \[ \left(\frac{3\lambda + 1}{\lambda + 1}\right)^2 < 4 \cdot 1 \] This simplifies to: \[ \left(\frac{3\lambda + 1}{\lambda + 1}\right)^2 < 4 \] ### Step 3: Solve the inequality Taking the square root of both sides (considering only the positive root since y is positive): \[ \frac{3\lambda + 1}{\lambda + 1} < 2 \] Cross-multiplying gives: \[ 3\lambda + 1 < 2(\lambda + 1) \] Expanding the right side: \[ 3\lambda + 1 < 2\lambda + 2 \] Rearranging gives: \[ 3\lambda - 2\lambda < 2 - 1 \] \[ \lambda < 1 \] ### Step 4: Find the lower bound for λ Now, we also need to ensure that the point R is between P and Q. Since R divides PQ in the ratio \(1 : \lambda\), \(\lambda\) must be greater than 0. ### Conclusion Thus, the value of \(\lambda\) must satisfy: \[ 0 < \lambda < 1 \] ### Final Answer The final answer is: \[ \lambda \in (0, 1) \]
Promotional Banner

Topper's Solved these Questions

  • PARABOLA

    OBJECTIVE RD SHARMA ENGLISH|Exercise Chapter Test|30 Videos
  • PARABOLA

    OBJECTIVE RD SHARMA ENGLISH|Exercise Section II - Assertion Reason Type|7 Videos
  • PAIR OF STRAIGHT LINES

    OBJECTIVE RD SHARMA ENGLISH|Exercise Chapter Test|18 Videos
  • PERMUTATIONS AND COMBINATIONS

    OBJECTIVE RD SHARMA ENGLISH|Exercise Chapter Test|60 Videos

Similar Questions

Explore conceptually related problems

Draw a perpendicular to a given line segment though a point R on the line segment .

The mid point of the line segment joining the points (-5, 7) and (-1, 3) is

The projection of the line segment joining the Points (1, 2, 3) and (4, 5, 6) on the plane 2x + y + z = 1 is

Comprehension (Q.6 to 8) A line is drawn through the point P(-1,2) meets the hyperbola x y=c^2 at the points A and B (Points A and B lie on the same side of P) and Q is a point on the lien segment AB. If the point Q is choosen such that PQ, PQ and PB are inAP, then locus of point Q is x+y(1+2x) (b) x=y(1+x) 2x=y(1+2x) (d) 2x=y(1+x)

The ratio in which the line segment joining the point (4, -6) and (3, 1) si divided by the parabola y^(2)=4ax is

If the line segment joining (2,3) and (-1,2) is divided internally in the ratio 3:4 by the line x+2y=lambda , then lambda =

Let P(2,-1,4) and Q(4,3,2) are two points and as point R on PQ is such that 3PQ=5QR , then the coordinates of R are

The point of injtersection of the line x/p+y/q=1 and x/q+y/p=1 lies on the line

If P=(1,1),Q=(3,2) and R is a point on x-axis then the value of PR+RQ will be minimum at

Let the tangents PQ and PR are drawn to y^(2)=4ax from any point P on the line x+4a=0 . The angle subtended by the chord of contact QR at the vertex of the parabola y^(2)=4ax is

OBJECTIVE RD SHARMA ENGLISH-PARABOLA-Exercise
  1. f the normal at the point P (at1, 2at1) meets the parabola y^2=4ax agu...

    Text Solution

    |

  2. The equation of the parabola whose vertex is at(2, -1) and focus at(2,...

    Text Solution

    |

  3. The ends of a line segment are P(1, 3) and Q(1,1), R is a point on th...

    Text Solution

    |

  4. The vertex of the parabola y^2+6x-2y+13=0 is

    Text Solution

    |

  5. The Cartesian equation of the directrix of the parabola whose parametr...

    Text Solution

    |

  6. If the vertex of a parabola is (0, 2) and the extremities of latusrect...

    Text Solution

    |

  7. A line L passing through the focus of the parabola (y-2)^(2)=4(x+1) in...

    Text Solution

    |

  8. Let y=f(x) be a parabola, having its axis parallel to the y-axis, whic...

    Text Solution

    |

  9. If two tangents drawn from the point (alpha,beta) to the parabola y^2=...

    Text Solution

    |

  10. The angle between the tangents drawn form the point (3, 4) to the para...

    Text Solution

    |

  11. set of values of m for which a chord of slope m of the circle x^2 + y^...

    Text Solution

    |

  12. The mid-point of the line joining the common points of the line 2x-3y+...

    Text Solution

    |

  13. Tangents PQ and PR are drawn to the parabola y^(2) = 20(x+5) and y^(2)...

    Text Solution

    |

  14. PC is the normal at P to the parabola y^(2) = 4ax, C being on the axis...

    Text Solution

    |

  15. From a fixed point A three normals are drawn to the parabola y^(2)=4ax...

    Text Solution

    |

  16. The tangent to the parabola y=x^2 has been drawn so that the abscissa ...

    Text Solution

    |

  17. A circle drawn on any focal AB of the parabola y^(2)=4ax as diameter c...

    Text Solution

    |

  18. Let F be the focus of the parabola y^(2)=4ax and M be the foot of perp...

    Text Solution

    |

  19. The focus of a parabola is (0, 0) and vertex (1, 1). If two mutually p...

    Text Solution

    |

  20. The point P on the parabola y^(2)=4ax for which | PR-PQ | is maximum, ...

    Text Solution

    |