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Four digit numbers with different digits...

Four digit numbers with different digits are formed using the digits `1,2,3,4,5,6,7,8`. One number from them is picked up at random. The chance that the selected number contains the digit '1' is

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To solve the problem of finding the probability that a randomly selected four-digit number formed using the digits 1, 2, 3, 4, 5, 6, 7, and 8 contains the digit '1', we can follow these steps: ### Step 1: Calculate the total number of four-digit numbers We can form a four-digit number using the digits 1 to 8, ensuring that all digits are different. - For the first digit, we can choose any of the 8 digits. - For the second digit, we can choose from the remaining 7 digits. - For the third digit, we can choose from the remaining 6 digits. - For the fourth digit, we can choose from the remaining 5 digits. Thus, the total number of four-digit numbers is calculated as: \[ \text{Total numbers} = 8 \times 7 \times 6 \times 5 \] ### Step 2: Calculate the number of four-digit numbers containing the digit '1' To find the number of four-digit numbers that contain the digit '1', we can fix '1' in one of the four positions and then fill the remaining three positions with the other digits. - We can fix '1' in one of the 4 positions (1st, 2nd, 3rd, or 4th). - For the remaining three positions, we can choose from the remaining 7 digits (2, 3, 4, 5, 6, 7, 8). The choices for the remaining three digits are: - For the first remaining position, we can choose from 7 digits. - For the second remaining position, we can choose from 6 digits. - For the third remaining position, we can choose from 5 digits. Thus, the total number of four-digit numbers containing the digit '1' is calculated as: \[ \text{Numbers containing '1'} = 4 \times (7 \times 6 \times 5) \] ### Step 3: Calculate the probability The probability \( P \) that a randomly selected four-digit number contains the digit '1' is given by the ratio of the number of favorable outcomes to the total number of outcomes: \[ P(\text{contains '1'}) = \frac{\text{Numbers containing '1'}}{\text{Total numbers}} = \frac{4 \times (7 \times 6 \times 5)}{8 \times (7 \times 6 \times 5)} \] ### Step 4: Simplify the probability We can simplify the expression: \[ P(\text{contains '1'}) = \frac{4}{8} = \frac{1}{2} \] ### Final Answer The probability that a randomly selected four-digit number contains the digit '1' is: \[ \frac{1}{2} \] ---

To solve the problem of finding the probability that a randomly selected four-digit number formed using the digits 1, 2, 3, 4, 5, 6, 7, and 8 contains the digit '1', we can follow these steps: ### Step 1: Calculate the total number of four-digit numbers We can form a four-digit number using the digits 1 to 8, ensuring that all digits are different. - For the first digit, we can choose any of the 8 digits. - For the second digit, we can choose from the remaining 7 digits. - For the third digit, we can choose from the remaining 6 digits. ...
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