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A team of 8 couples (husband and wife) attend a lucky draw in which 4 persons picked for a prize. Then the probability that there is at least one couple is

A

`11//39`

B

`12//39`

C

`14//39`

D

`15//39`

Text Solution

Verified by Experts

The correct Answer is:
D

We have,
Probability of selecting at least one couple for the prize
`=1-` Probability of not selecting any couple for the prize
`=1-((.^(16)C_(1)xx .^(14)C_(1)xx .^(12)C_(1)xx .^(10)C_(1)4!))/(.^(16)C_(4))`
`=1-(16xx14xx12xx10)/(16xx15xx14xx13)=(15)/(39)`.
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