If there are 6 girls and 5 boys who sit ...

If there are 6 girls and 5 boys who sit in a row, then the probability that no two boys sit together is :

`(6! 6!)/(2! 11 !)`

`(7! 5!)/(2! 11 !)`

`(6 ! 7 !)/(2! 11 !)`

none of these

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