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The equation of the tangent parallel to `y=x` drawn to `(x^(2))/(3)-(y^(2))/(2)=1`, is

A

`x-y+1=0`

B

`x-y+2=0`

C

`x-y+3=0`

D

`x-y-2=0`

Text Solution

Verified by Experts

Let `y=x+c` be the required tangent. Then,
`c^(2)=3xx1^(2)-2impliesc=+-1` [ Using `c^(2)=a^(2)m^(2)-b^(2)`]
Hence required tangents are `y=x+-1`.
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