Home
Class 11
MATHS
If the quadrilateral formed by the lines...

If the quadrilateral formed by the lines ax+bc+c=0. a'x+b'y+c=0, ax+by+c'=0, a'x+b'y+c'=0 has perpendicular diagonal, then

A

`b^(2) + c^(2) = b^(2) + c^(2)`

B

`c^(2) + a^(2) = c^(2) +a^(2)`

C

`a^(2) + b^(2) =a^(2) + b^(2)`

D

none of these

Text Solution

Verified by Experts

The correct Answer is:
C

Since the diagonal are perpendicular, so the given quadrilateral is a rhombus.
`therefore ` Distance between two pairs of parallel sides are equal
`rArr |(c'-c)/(sqrt(a^(2) +b^(2)))|=|(c'-c)/(sqrt(a^(2)+b^(2)))|rArr a^(2) + b^(2) = a^(2) + b^(2)`
Doubtnut Promotions Banner Mobile Dark
|

Topper's Solved these Questions

  • STRAIGHT LINES

    OBJECTIVE RD SHARMA ENGLISH|Exercise Section-1 Solved MCQs (Example)|1 Videos
  • STRAIGHT LINES

    OBJECTIVE RD SHARMA ENGLISH|Exercise SECTION - II (ASSERTION - REASON TYPE MCQs)|14 Videos
  • STRAIGHT LINES

    OBJECTIVE RD SHARMA ENGLISH|Exercise ILLUSTRATION 18|1 Videos
  • SETS

    OBJECTIVE RD SHARMA ENGLISH|Exercise Chapter Test|30 Videos

Similar Questions

Explore conceptually related problems

If the quadrilateral formed by the lines ax+by+c=0, 6sqrt(3)x+8sqrt(3)y+k=0 , ax+by+k=0 and 6sqrt(3)x + 8sqrt(3)y+c=0 has diagonals at right angles, then the value of a^2 +b^2 = …

If the quadrilateral formed by the lines a x+b y+c=0,a^(prime)x+b^(prime)y+c=0,a x+b y+c^(prime)=0,a^(prime)x+b^(prime)y+c^(prime)=0 has perpendicular diagonals, then (a) b^2+c^2=b^('2)+c^('2) (b) c^2+a^2=c^('2)+a^('2) (c) a^2+b^2=a^('2)+b^('2) (d) none of these

If the quadrilateral formed by the lines a x+b y+c=0,a^(prime)x+b^(prime)y+c=0,a x+b y+c^(prime)=0,a^(prime)x+b^(prime)y+c^(prime)=0 has perpendicular diagonals, then b^2+c^2=b^('2)+c^('2) c^2+a^2=c^('2)+a^('2) a^2+b^2=a^('2)+b^('2) (d) none of these

If a, c, b are in G.P then the line ax + by + c= 0

The equation ax+by +c=0 represents a plane perpendicular to the

Find the distance between the parallel lines ax+by+c=0 and ax+by+d=0

Show that the parallelogram formed by ax+by+c=0, a_1 x+ b_1 y+c=0, ax+by+c_1 =0 and a_1 x+b_1 y+c_1 =0 will be a rhombus if a^2 +b^2 = (a_1)^2 + (b_1)^2 .

If the line ax+by+c=0 is normal to the xy+5=0 , then a and b have

The algebraic sum of distances of the line ax + by + 2 = 0 from (1,2), (2,1) and (3,5) is zero and the lines bx - ay + 4 = 0 and 3x + 4y + 5=0 cut the coordinate axes at concyclic points. Then (a) a+b=-2/7 (b) area of triangle formed by the line ax+by+2=0 with coordinate axes is 14/5 (c) line ax+by+3=0 always passes through the point (-1,1) (d) max {a,b}=5/7

The equation of the plane through the line of intersection of the planes ax + by+cz + d= 0 and a'x + b'y+c'z + d'= 0 parallel to the line y=0 and z=0 is