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Equation of the bisector of angle B of t...

Equation of the bisector of angle B of the triangle ABC is `y = x`. If A is `(2,6)` and B is `(1, 1)`; equation of side BC is (A) `2x + y - 3 = 0` (B) `x-5y+ 4 =0` (C) `x- 6y + 5 = 0` (D) none of these

A

2x + y - 3 = 0

B

x - 5y + 4 = 0

C

x - 6y + 5 = 0

D

none of these

Text Solution

Verified by Experts

The reflection or image of A (2,6) in the line mirror y =x will lie on BC. The reflection of A is P (6,2) . So , the equation of BC is
`y -1 = (2-1)/(6-1) (x - 1) implies x - 5y + 4 = 0 `
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