distance of the lines `2x-3y-4=0` from the point `(1, 1)` measured paralel to the line `x+y=1` is

Options

A. `sqrt2`
B. `(5)/(sqrt2)`
C. `(1)/(sqrt2)`
D. 6

Explanation

To find the distance of the line \(2x - 3y - 4 = 0\) from the point \((1, 1)\) measured parallel to the line \(x + y = 1\), we can follow these steps:

### Step 1: Find the equation of the line parallel to \(x + y = 1\) that passes through the point \((1, 1)\).

The equation of a line parallel to \(x + y = 1\) can be expressed as:
\[ x + y + c = 0 \]
...