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Let P S be the median of the triangle...

Let `P S` be the median of the triangle with vertices `P(2,2),Q(6,-1)a n dR(7,3)` Then equation of the line passing through `(1,-1)` and parallel to `P S` is `2x-9y-7=0` `2x-9y-11=0` `2x+9y-11=0` `2x+9y+7=0`

A

4x + 7y + 3 = 0

B

2x - 9y - 11 = 0

C

4x - 7y + 11 = 0

D

2x + 9y + 7 = 0

Text Solution

Verified by Experts

The correct Answer is:
D
The slope of PS is m = `(1 - 2)/((13)/(2) - 2) = - (2)/(9)`
So , the equation of the line passing through (1,-1) and parallel to PS is

`y + 1 = - (2)/(9) (x - 1) or , 2x + 9y + 7 = 0`
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