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If the line x+y-1=(lamda)/(2)=0 passin...

If the line `x+y-1=(lamda)/(2)=0` passing through the intersection of `x-y+1=0` and `3x+y-5=0` is perpendicular to one of them, then the value of `lamda` is:

A

x + y + 3 = 0

B

x - y -3 = 0

C

x - 3y - 5 =0

D

x -3y + 5 = 0

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The correct Answer is:
D
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OBJECTIVE RD SHARMA ENGLISH-STRAIGHT LINES-Exercise
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