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The distance of the line x + y - 8 = 0 f...

The distance of the line x + y - 8 = 0 from (4,1) measured along the direction whose slope is -2 , is

A

`3sqrt5`

B

`6 sqrt5`

C

`2 sqrt5`

D

none of these

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AI Generated Solution

The correct Answer is:
To find the distance of the line \(x + y - 8 = 0\) from the point \((4, 1)\) measured along the direction whose slope is \(-2\), we can follow these steps: ### Step-by-Step Solution: 1. **Identify the given line and point**: The line is given by the equation: \[ x + y - 8 = 0 \] The point from which we want to measure the distance is \((4, 1)\). 2. **Check if the point lies on the line**: Substitute the coordinates of the point into the line equation: \[ 4 + 1 - 8 = -3 \quad (\text{not on the line}) \] Since the result is not zero, the point \((4, 1)\) does not lie on the line. 3. **Determine the slope of the line**: The slope of the line \(x + y - 8 = 0\) can be rearranged to the slope-intercept form: \[ y = -x + 8 \] Thus, the slope of the line is \(-1\). 4. **Determine the slope of the direction**: The slope of the direction along which we are measuring the distance is given as \(-2\). 5. **Find the equation of the line in the direction of slope -2 through the point (4, 1)**: Using point-slope form: \[ y - 1 = -2(x - 4) \] Simplifying this: \[ y - 1 = -2x + 8 \implies 2x + y - 9 = 0 \] 6. **Find the intersection of the two lines**: We need to solve the system of equations: \[ x + y - 8 = 0 \quad \text{(1)} \] \[ 2x + y - 9 = 0 \quad \text{(2)} \] Subtract equation (1) from equation (2): \[ (2x + y - 9) - (x + y - 8) = 0 \] This simplifies to: \[ 2x + y - 9 - x - y + 8 = 0 \implies x - 1 = 0 \implies x = 1 \] Substitute \(x = 1\) back into equation (1): \[ 1 + y - 8 = 0 \implies y = 7 \] Thus, the point of intersection is \((1, 7)\). 7. **Calculate the distance between the points (4, 1) and (1, 7)**: Using the distance formula: \[ d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2} \] where \((x_1, y_1) = (4, 1)\) and \((x_2, y_2) = (1, 7)\): \[ d = \sqrt{(1 - 4)^2 + (7 - 1)^2} = \sqrt{(-3)^2 + (6)^2} = \sqrt{9 + 36} = \sqrt{45} = 3\sqrt{5} \] ### Final Answer: The distance from the line \(x + y - 8 = 0\) to the point \((4, 1)\) measured along the direction whose slope is \(-2\) is: \[ \boxed{3\sqrt{5}} \]
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