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Prove that the area of the parallelogram...

Prove that the area of the parallelogram formed by the lines `xcosalpha+ysinalpha=p ,xcosalpha+ys inalpha=q ,xcosbeta+ysinbeta=ra n dx cosbeta+ysinbeta=si s+-(p-q)(r-s)cos e c(alpha-beta)dot`

A

`pm (pi)/(2)`

B

`(pi)/(4)`

C

`(pi)/(6)`

D

`(pi)/(3)`

Text Solution

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The correct Answer is:
B
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OBJECTIVE RD SHARMA ENGLISH-STRAIGHT LINES-Exercise
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  17. The line PQ whose equation is x-y = 2 cuts the x-axis at P, and Q is (...

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