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The equations of two sides of a square w...

The equations of two sides of a square whose area is 25 sq.units are `3-4y=0 and 4x+3y=0.` The equation of the other two sides of the square are

A

`3x-4ypm25=0, 4x+3y pm 25=0`

B

`3x-4ypm05=0, 4x+3y pm 5=0`

C

`3x-4y pm 05=0 , 4x+3y pm=0`

D

none of these

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The correct Answer is:
To find the equations of the other two sides of a square given the equations of two sides, we can follow these steps: ### Step 1: Identify the Given Equations The equations of the two sides of the square are: 1. \( 3x - 4y = 0 \) 2. \( 4x + 3y = 0 \) ### Step 2: Determine the Slopes of the Given Lines We can rewrite the equations in slope-intercept form \( y = mx + b \) to find their slopes. 1. For \( 3x - 4y = 0 \): \[ 4y = 3x \implies y = \frac{3}{4}x \] The slope \( m_1 = \frac{3}{4} \). 2. For \( 4x + 3y = 0 \): \[ 3y = -4x \implies y = -\frac{4}{3}x \] The slope \( m_2 = -\frac{4}{3} \). ### Step 3: Find the Length of the Side of the Square The area of the square is given as \( 25 \) sq. units. The side length \( a \) can be calculated as: \[ a^2 = 25 \implies a = 5 \] ### Step 4: Calculate the Distance Between the Parallel Lines The distance \( d \) between two parallel lines can be calculated using the formula: \[ d = \frac{|c_1 - c_2|}{\sqrt{a^2 + b^2}} \] For the first line \( 3x - 4y = 0 \) (rewritten as \( 3x - 4y + 0 = 0 \)), \( c_1 = 0 \). For the second line \( 4x + 3y = 0 \) (rewritten as \( 4x + 3y + 0 = 0 \)), \( c_2 = 0 \). ### Step 5: Set Up the Equations for the Other Two Sides The equations of the other two sides will be parallel to the given lines. Since the distance between the sides of the square is equal to the side length \( a = 5 \), we can write: 1. For the line parallel to \( 3x - 4y = 0 \): \[ 3x - 4y + d = 0 \quad \text{where } d = \pm 25 \] Thus, the equations become: \[ 3x - 4y + 25 = 0 \quad \text{and} \quad 3x - 4y - 25 = 0 \] 2. For the line parallel to \( 4x + 3y = 0 \): \[ 4x + 3y + d = 0 \quad \text{where } d = \pm 25 \] Thus, the equations become: \[ 4x + 3y + 25 = 0 \quad \text{and} \quad 4x + 3y - 25 = 0 \] ### Final Equations The equations of the other two sides of the square are: 1. \( 3x - 4y + 25 = 0 \) 2. \( 3x - 4y - 25 = 0 \) 3. \( 4x + 3y + 25 = 0 \) 4. \( 4x + 3y - 25 = 0 \)
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OBJECTIVE RD SHARMA ENGLISH-STRAIGHT LINES-Exercise
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  4. Centroid of the triangle, the equations of whose sides are 12x^(2)-20x...

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  5. If the lines a x+2y+1=0,b x+3y+1=0a n dc x+4y+1=0 are concurrent, then...

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  6. Two vertices of a triangle are (5,-1) and (-2,3) If the orthocentre of...

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  7. If the foot of the perpendicular from the origin to a straight line is...

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  8. A rectangle has two opposite vertices at the points (1,2) a n d (5,5)....

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  9. The orthocentre of the triangle formed by the lines x y=0 and x+y=1 is...

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  10. A line passes through the point (2,2) and is perpendicular to the line...

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  11. A line passes through (2, 2) and is perpendicular to the line 3x+y=3. ...

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  12. Given three straight lines 2x+11 y-5=0,24 x+7y-20=0, and 4x-3y-2=0 . T...

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  13. A line passes through the point of intersection of the line 3x+y+1=0 a...

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  14. A straight line through the point (2,2) intersects the lines sqrt(3)x+...

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  15. Find the image of the point (3,8) with respect to the line x+3y=7 assu...

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