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If x=2+a+a^2+oo,w h e r e|a|<1a n dy=1+b...

If `x=2+a+a^2+oo,w h e r e|a|<1a n dy=1+b+b^2+oo,w h e r e|b|<1.` prove that: `1+a b+a^2b^2+oo=(x y)/(x+y-1)`

A

`(xy)/(y+x-1)`

B

`(x+y)/(x-y)`

C

`(x^(2)+y^(2))/(x-y)`

D

`(xy)/(y+x+1)`

Text Solution

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The correct Answer is:
A
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OBJECTIVE RD SHARMA ENGLISH-SEQUENCES AND SERIES-Exercise
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