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If H be the H.M. between a and b, then t...

If H be the H.M. between a and b, then the value of `(H)/(a)+(H)/(b)` is

A

2

B

`(ab)/(a+b)`

C

`(a+b)/(ab)`

D

none of these

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The correct Answer is:
To solve the problem, we need to find the value of \(\frac{H}{a} + \frac{H}{b}\) where \(H\) is the harmonic mean between \(a\) and \(b\). ### Step-by-Step Solution: 1. **Definition of Harmonic Mean**: The harmonic mean \(H\) of two numbers \(a\) and \(b\) is given by the formula: \[ H = \frac{2ab}{a + b} \] 2. **Calculate \(\frac{H}{a}\)**: We start by substituting the value of \(H\) into \(\frac{H}{a}\): \[ \frac{H}{a} = \frac{\frac{2ab}{a + b}}{a} = \frac{2ab}{a(a + b)} = \frac{2b}{a + b} \] 3. **Calculate \(\frac{H}{b}\)**: Next, we calculate \(\frac{H}{b}\): \[ \frac{H}{b} = \frac{\frac{2ab}{a + b}}{b} = \frac{2ab}{b(a + b)} = \frac{2a}{a + b} \] 4. **Combine \(\frac{H}{a}\) and \(\frac{H}{b}\)**: Now, we add \(\frac{H}{a}\) and \(\frac{H}{b}\): \[ \frac{H}{a} + \frac{H}{b} = \frac{2b}{a + b} + \frac{2a}{a + b} \] 5. **Simplifying the Expression**: Since both fractions have the same denominator, we can combine them: \[ \frac{H}{a} + \frac{H}{b} = \frac{2b + 2a}{a + b} = \frac{2(a + b)}{a + b} \] 6. **Final Result**: The \(a + b\) in the numerator and denominator cancels out: \[ \frac{H}{a} + \frac{H}{b} = 2 \] Thus, the value of \(\frac{H}{a} + \frac{H}{b}\) is \(2\).
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OBJECTIVE RD SHARMA ENGLISH-SEQUENCES AND SERIES-Exercise
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  3. If H be the H.M. between a and b, then the value of (H)/(a)+(H)/(b) is

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  4. The sum of n terms of two arithmetic progressions are in the ratio 2n+...

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  14. An A.P., and a H.P. have the same first and last terms and the same od...

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