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If a,b,c are any three consecutive integ...

If a,b,c are any three consecutive integers , prove that `log(1+ac)=2logb`

A

`"log" b`

B

`"log" ((b)/(2))`

C

`"log" (2b)`

D

`2"log"b`

Text Solution

Verified by Experts

The correct Answer is:
D

Since a, b, c are three consective positive integers,
`therefore b = a + 1, c= a + 2 " and " 2b = a+ c`
Now,
`"log" (1+ca)`
`= "log"{1+(a+2)a} = "log" (a+1)^(2) = 2"log" (a+1) = 2 "log" b`
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