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If log10 343 = 2.5353 then the least pos...

If `log_10 343 = 2.5353` then the least positive integer 'n' such that `7^n>10^5` is

A

1

B

6

C

5

D

4

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AI Generated Solution

The correct Answer is:
To solve the problem, we need to find the least positive integer \( n \) such that \( 7^n > 10^5 \). We are given that \( \log_{10} 343 = 2.5353 \). ### Step-by-Step Solution: 1. **Express 343 in terms of base 7**: \[ 343 = 7^3 \] Therefore, we can write: \[ \log_{10} 343 = \log_{10} (7^3) = 3 \log_{10} 7 \] 2. **Relate \( \log_{10} 7 \) to the given value**: From the equation above, we have: \[ 3 \log_{10} 7 = 2.5353 \] To find \( \log_{10} 7 \), we divide both sides by 3: \[ \log_{10} 7 = \frac{2.5353}{3} \approx 0.8451 \] 3. **Set up the inequality**: We need to find \( n \) such that: \[ 7^n > 10^5 \] Taking logarithm (base 10) on both sides gives: \[ \log_{10} (7^n) > \log_{10} (10^5) \] This simplifies to: \[ n \log_{10} 7 > 5 \] 4. **Substitute the value of \( \log_{10} 7 \)**: Substitute \( \log_{10} 7 \) into the inequality: \[ n \cdot 0.8451 > 5 \] 5. **Solve for \( n \)**: To isolate \( n \), divide both sides by \( 0.8451 \): \[ n > \frac{5}{0.8451} \approx 5.917 \] 6. **Determine the least positive integer \( n \)**: Since \( n \) must be a positive integer, we round up \( 5.917 \) to the next whole number: \[ n = 6 \] ### Conclusion: The least positive integer \( n \) such that \( 7^n > 10^5 \) is \( \boxed{6} \).
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