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If "log"(10)5 =x, " then log"(5) 1250 eq...

If `"log"_(10)5 =x, " then log"_(5) 1250` equals to

A

`3-(1)/(x)`

B

`2+(1)/(x)`

C

`3+(1)/(x)`

D

`2-(1)/(x)`

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem, we need to find the value of \( \log_5 1250 \) given that \( \log_{10} 5 = x \). ### Step-by-Step Solution: 1. **Rewrite the Expression**: \[ \log_5 1250 = \log_5 (125 \times 10) \] **Hint**: Break down the number 1250 into its prime factors or simpler components. 2. **Apply the Logarithm Property**: Using the property \( \log_a (b \times c) = \log_a b + \log_a c \), we can rewrite the expression: \[ \log_5 1250 = \log_5 125 + \log_5 10 \] **Hint**: Remember that logarithms can be split into the sum of logarithms when multiplying. 3. **Simplify \( \log_5 125 \)**: Since \( 125 = 5^3 \), we can use the power rule of logarithms: \[ \log_5 125 = \log_5 (5^3) = 3 \] **Hint**: The power rule states that \( \log_a (b^c) = c \cdot \log_a b \). 4. **Express \( \log_5 10 \)**: We can use the change of base formula: \[ \log_5 10 = \frac{1}{\log_{10} 5} \] Given \( \log_{10} 5 = x \), we have: \[ \log_5 10 = \frac{1}{x} \] **Hint**: The change of base formula allows you to convert logarithms to different bases. 5. **Combine the Results**: Now, substitute back into the expression: \[ \log_5 1250 = 3 + \frac{1}{x} \] **Hint**: Combine the results from the previous steps to get the final expression. ### Final Answer: Thus, the value of \( \log_5 1250 \) is: \[ \log_5 1250 = 3 + \frac{1}{x} \]
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OBJECTIVE RD SHARMA ENGLISH-LOGARITHMS-Exercise
  1. 2^(x)xx3^(2x)=100 then x belongs to

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  2. If x^(2"log"(10)x) = 1000x, then x equals to

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  3. If "log"(10)5 =x, " then log"(5) 1250 equals to

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  7. If a =log3(5) and b =log17( 25), which one of the following is correct...

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  8. If x ="log"(a)(bc), y ="log"(b)(ca) " and "z = "log"(c)(ab), then whi...

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  9. The value of "log"(2)"log"(2)"log"(4) 256 + 2 "log"(sqrt(2))2, is

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  11. If "log"(2) 7 = x, then x is:

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  12. If 2^((3)/("log"(3)x)) = (1)/(64), then x =

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  13. If a = 1 + log(x) yz, b = 1 + log(y) zx and c = 1 + log xy where x, ...

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  14. If (logx)/(a^2+a b+b^2)=(logy)/(b^2+b c+c^2)=(logz)/(c^2+c a+a^2), the...

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  15. If log(2a-3b)=loga-logb, then a=

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  16. If ("log"3)/(x-y) = ("log"5)/(y-z) = ("log" 7)/(z-x), " then " 3^(x+y)...

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  19. The value of (0.16)^log2.5{1/3+1/3^2+...} is

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  20. if a^2+4b^2=12ab, then log(a+2b)

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