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Number of possible value(s) of integer '...

Number of possible value(s) of integer 'a' for which the quadratic equation `x^(2) + ax + 16 = 0` has integral roots, is

A

4

B

6

C

2

D

none of these

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To find the number of possible integer values of 'a' for which the quadratic equation \( x^2 + ax + 16 = 0 \) has integral roots, we can follow these steps: ### Step 1: Understand the condition for integral roots For the quadratic equation \( ax^2 + bx + c = 0 \) to have integral roots, the discriminant \( D \) must be a perfect square. The discriminant \( D \) for our equation is given by: \[ D = b^2 - 4ac \] In our case, \( a = a \), \( b = a \), and \( c = 16 \). Therefore, the discriminant becomes: \[ D = a^2 - 4 \cdot 1 \cdot 16 = a^2 - 64 \] ### Step 2: Set the discriminant as a perfect square We set the discriminant equal to a perfect square: \[ a^2 - 64 = k^2 \] where \( k \) is an integer. Rearranging gives: \[ a^2 - k^2 = 64 \] This can be factored using the difference of squares: \[ (a - k)(a + k) = 64 \] ### Step 3: Find the factor pairs of 64 Next, we need to find the integer factor pairs of 64. The pairs are: 1. \( (1, 64) \) 2. \( (2, 32) \) 3. \( (4, 16) \) 4. \( (8, 8) \) 5. \( (-1, -64) \) 6. \( (-2, -32) \) 7. \( (-4, -16) \) 8. \( (-8, -8) \) ### Step 4: Solve for 'a' from each factor pair For each factor pair \( (m, n) \), we have: \[ a - k = m \quad \text{and} \quad a + k = n \] Adding these two equations gives: \[ 2a = m + n \implies a = \frac{m + n}{2} \] Subtracting the first equation from the second gives: \[ 2k = n - m \implies k = \frac{n - m}{2} \] Now we will calculate 'a' for each factor pair: 1. For \( (1, 64) \): \[ a = \frac{1 + 64}{2} = \frac{65}{2} \quad \text{(not an integer)} \] 2. For \( (2, 32) \): \[ a = \frac{2 + 32}{2} = 17 \quad \text{(integer)} \] 3. For \( (4, 16) \): \[ a = \frac{4 + 16}{2} = 10 \quad \text{(integer)} \] 4. For \( (8, 8) \): \[ a = \frac{8 + 8}{2} = 8 \quad \text{(integer)} \] 5. For \( (-1, -64) \): \[ a = \frac{-1 - 64}{2} = -32.5 \quad \text{(not an integer)} \] 6. For \( (-2, -32) \): \[ a = \frac{-2 - 32}{2} = -17 \quad \text{(integer)} \] 7. For \( (-4, -16) \): \[ a = \frac{-4 - 16}{2} = -10 \quad \text{(integer)} \] 8. For \( (-8, -8) \): \[ a = \frac{-8 - 8}{2} = -8 \quad \text{(integer)} \] ### Step 5: List all possible integer values of 'a' The possible integer values of 'a' are: - \( 17 \) - \( 10 \) - \( 8 \) - \( -17 \) - \( -10 \) - \( -8 \) ### Conclusion Thus, the number of possible integer values of 'a' is \( 6 \).

To find the number of possible integer values of 'a' for which the quadratic equation \( x^2 + ax + 16 = 0 \) has integral roots, we can follow these steps: ### Step 1: Understand the condition for integral roots For the quadratic equation \( ax^2 + bx + c = 0 \) to have integral roots, the discriminant \( D \) must be a perfect square. The discriminant \( D \) for our equation is given by: \[ D = b^2 - 4ac \] In our case, \( a = a \), \( b = a \), and \( c = 16 \). Therefore, the discriminant becomes: ...
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OBJECTIVE RD SHARMA ENGLISH-QUADRATIC EXPRESSIONS AND EQUATIONS -Section I - Solved Mcqs
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  2. If ax^(2)+bx+c = 0 has no real roots and a, b, c in R such that a + c ...

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  10. The equation |x+1||x-1|=a^(2) - 2a - 3 can have real solutions for x, ...

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  11. If x^(2) - px + q = 0 has equal integral roots, then

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  12. Let A, G, and H are the A.M., G.M. and H.M. respectively of two unequa...

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  13. If b is the harmonic mean of a and c and alpha, beta are the roots of ...

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  14. If the expression a^(2)(b^(2)-c^(2))x^(2)+b^(2)(c^(2)-a^(2))x+c^(2)(a^...

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  15. Let pa n dq be the roots of the equation x^2-2x+A=0 and let ra n ds be...

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  16. The equation x^(2) + ax+b^2=0 has two roots each of which exceeds a ...

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  17. If ax^(2) + bx + 10 = 0 does not have two distinct real roots, then th...

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  18. For the equation 2x^(2) + 6 sqrt(2)x + 1 = 0

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  19. The value of a for which exactly one root of the equation e^ax^2 - e^(...

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  20. Let f(x) =ax^2 + bx+ c AA a, b, c in R, a != 0 satisfying f (1) + f(2...

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