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IF the equations x^(3) + 5x^(2) + px + q...

IF the equations `x^(3) + 5x^(2) + px + q = 0 and x^(3) + 7x^(2) + px + r = 0` have two roots in common, then the product of two non-common roots of two equations, is

A

35

B

-35

C

35 + p - q

D

35 + p + q - r

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The correct Answer is:
To solve the problem, we need to analyze the two cubic equations given and find the product of the two non-common roots. Let's denote the roots of the first equation as \( \alpha, \beta, x_1 \) and the roots of the second equation as \( \alpha, \beta, x_2 \). ### Step-by-Step Solution: 1. **Identify the equations and their roots:** - The first equation is \( x^3 + 5x^2 + px + q = 0 \) with roots \( \alpha, \beta, x_1 \). - The second equation is \( x^3 + 7x^2 + px + r = 0 \) with roots \( \alpha, \beta, x_2 \). 2. **Use Vieta's formulas to express the sums of the roots:** - For the first equation: \[ \alpha + \beta + x_1 = -5 \] - For the second equation: \[ \alpha + \beta + x_2 = -7 \] 3. **Express the product of the roots:** - For the first equation: \[ \alpha\beta + \beta x_1 + \alpha x_1 = p \] - For the second equation: \[ \alpha\beta + \beta x_2 + \alpha x_2 = p \] 4. **Equate the two equations for \( p \):** Since both equations equal \( p \), we can set them equal to each other: \[ \alpha\beta + x_1(\alpha + \beta) = \alpha\beta + x_2(\alpha + \beta) \] 5. **Simplify the equation:** - Cancel \( \alpha\beta \) from both sides: \[ x_1(\alpha + \beta) = x_2(\alpha + \beta) \] - If \( \alpha + \beta \neq 0 \), we can divide both sides by \( \alpha + \beta \): \[ x_1 = x_2 \] - However, since \( x_1 \) and \( x_2 \) are roots of different equations, they cannot be equal. Thus, we conclude: \[ \alpha + \beta = 0 \] 6. **Substitute \( \alpha + \beta = 0 \) back into the equations:** - From \( \alpha + \beta + x_1 = -5 \): \[ 0 + x_1 = -5 \implies x_1 = -5 \] - From \( \alpha + \beta + x_2 = -7 \): \[ 0 + x_2 = -7 \implies x_2 = -7 \] 7. **Calculate the product of the non-common roots:** - The non-common roots are \( x_1 \) and \( x_2 \): \[ x_1 \cdot x_2 = (-5) \cdot (-7) = 35 \] ### Final Answer: The product of the two non-common roots of the two equations is \( 35 \).

To solve the problem, we need to analyze the two cubic equations given and find the product of the two non-common roots. Let's denote the roots of the first equation as \( \alpha, \beta, x_1 \) and the roots of the second equation as \( \alpha, \beta, x_2 \). ### Step-by-Step Solution: 1. **Identify the equations and their roots:** - The first equation is \( x^3 + 5x^2 + px + q = 0 \) with roots \( \alpha, \beta, x_1 \). - The second equation is \( x^3 + 7x^2 + px + r = 0 \) with roots \( \alpha, \beta, x_2 \). ...
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