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Let a, b, c be real numbers such that ax...

Let a, b, c be real numbers such that `ax^(2) + bx + c = 0 and x^(2) + x + 1 = 0` have a common root.
Statement-1: a = b = c
Staement-2: Two quadratic equations with real coefficients cannot have only one imainary root common.

A

Statement-1 is True, Statement-2 is True, Statement-2 is a correct explanation for Statement-1.

B

Statement-1 is True, Statement-2 is True, Statement-2 is not a correct explanation for Statement-1.

C

Statement-1 is True, Statement-2 is False.

D

Statement-1 is False, Statement-2 is True.

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To solve the problem, we need to analyze the two quadratic equations given: 1. \( ax^2 + bx + c = 0 \) 2. \( x^2 + x + 1 = 0 \) We are told that these two equations have a common root. Let's follow the steps to find out what this implies about the coefficients \( a, b, \) and \( c \). ### Step 1: Find the roots of the second equation The roots of the equation \( x^2 + x + 1 = 0 \) can be found using the quadratic formula: \[ x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a} \] Here, \( a = 1 \), \( b = 1 \), and \( c = 1 \). Plugging these values into the formula: \[ x = \frac{-1 \pm \sqrt{1^2 - 4 \cdot 1 \cdot 1}}{2 \cdot 1} = \frac{-1 \pm \sqrt{1 - 4}}{2} = \frac{-1 \pm \sqrt{-3}}{2} \] This simplifies to: \[ x = \frac{-1 \pm i\sqrt{3}}{2} \] Thus, the roots of the equation \( x^2 + x + 1 = 0 \) are \( \frac{-1 + i\sqrt{3}}{2} \) and \( \frac{-1 - i\sqrt{3}}{2} \). ### Step 2: Understand the implications of a common root Since \( ax^2 + bx + c = 0 \) has a common root with \( x^2 + x + 1 = 0 \), it must also have imaginary roots. The common root must be one of the roots we found above, either \( \frac{-1 + i\sqrt{3}}{2} \) or \( \frac{-1 - i\sqrt{3}}{2} \). ### Step 3: Equate the two equations For the two equations to have the same roots, the coefficients \( a, b, c \) must be proportional to the coefficients of \( x^2 + x + 1 \). Therefore, we can write: \[ \frac{a}{1} = \frac{b}{1} = \frac{c}{1} \] This implies that \( a = b = c \). ### Step 4: Validate the statements - **Statement 1**: \( a = b = c \) is true based on our analysis. - **Statement 2**: It states that two quadratic equations with real coefficients cannot have only one imaginary root in common. This is also true because if they have one common imaginary root, they must have both roots in common (since complex roots come in conjugate pairs). ### Conclusion Both statements are true.

To solve the problem, we need to analyze the two quadratic equations given: 1. \( ax^2 + bx + c = 0 \) 2. \( x^2 + x + 1 = 0 \) We are told that these two equations have a common root. Let's follow the steps to find out what this implies about the coefficients \( a, b, \) and \( c \). ### Step 1: Find the roots of the second equation ...
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OBJECTIVE RD SHARMA ENGLISH-QUADRATIC EXPRESSIONS AND EQUATIONS -Section II - Assertion Reason Type
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  2. Statement-1: If alpha and beta are real roots of the quadratic equatio...

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  3. Statement-1: If a, b, c, A, B, C are real numbers such that a lt b lt ...

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  4. Statement I: x^2-5x+6<0 if 2 < x < 3 Statement II: If alpha and beta, ...

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  5. about to only mathematics

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  6. Statement-1: There is a value of k for which the equation x^(3) - 3x +...

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  7. Statement-1: If x^(2) + ax + 4 gt 0 "for all" x in R, then a in (-4, 4...

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  8. If the roots of the equation ax^2 + bx + c = 0, a != 0 (a, b, c are re...

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  9. Statement (1) : If a and b are integers and roots of x^2 + ax + b = 0 ...

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  10. Statement-1: If a, b, c are distinct real numbers, then a((x-b)(x-c))/...

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  11. Let f(x)=a x^2+bx +c a ,b ,c in R. If f(x) takes real values for re...

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  12. Statement-1: If a, b, c in R and 2a + 3b + 6c = 0, then the equation a...

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  13. Statement-1: If a ne 0 and the equation ax^(2) + bx + c = 0 has two ro...

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  14. Statement-1: If a, b, c in Q and 2^(1//3) is a root of ax^(2) + bx + c...

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  15. Statement-1: If f(x) = 1 + x + (x^(2))/(2!) + (x^(3))/(3!) + (x^(4))/(...

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  16. Given that for all real x, the expression (x^(2)-2x+4)/(x^(2)+2x+4) l...

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  17. Let a, b, c be real numbers such that ax^(2) + bx + c = 0 and x^(2) + ...

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  18. Statement-1: The cubic equation 4x^(3) - 15x^(2)+14x-5 = 0 has a root ...

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  19. Statement-1: The equation (pi^(e))/(x-e)+(e^(pi))/(x-pi)+(pi^(pi)+e^(e...

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  20. Consider a quadratic equation ax^(2) + bx + c = 0, where 2a + 3b + 6c ...

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