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Given that a x^2+b x+c=0 has no real roo...

Given that `a x^2+b x+c=0` has no real roots and `a+b+c<0,` then `c!=0` b. `c<0` c. `c >0` d. `c=0`

A

c = 0

B

`c gt 0`

C

`c lt 0`

D

c = 0

Text Solution

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The correct Answer is:
C
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