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If the slopes of the lines given by ax^(...

If the slopes of the lines given by `ax^(2)+2hxy+by^(2)=0` are in the ratio `3:1`, then `h^(2)=`

A

`(ab)/(3)`

B

`(4ab)/(3)`

C

`(4a)/(3b)`

D

none of these

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The correct Answer is:
To solve the problem, we start with the equation of the pair of straight lines given by: \[ ax^2 + 2hxy + by^2 = 0 \] We need to find \( h^2 \) given that the slopes of the lines are in the ratio \( 3:1 \). ### Step 1: Rewrite the equation We can rewrite the equation by dividing through by \( x^2 \): \[ \frac{a}{x^2} + \frac{2h}{x} \cdot \frac{y}{x} + \frac{b}{x^2} \cdot \left(\frac{y}{x}\right)^2 = 0 \] Let \( m = \frac{y}{x} \). Then the equation becomes: \[ am^2 + 2hm + b = 0 \] ### Step 2: Identify the slopes The roots of this quadratic equation \( am^2 + 2hm + b = 0 \) represent the slopes of the lines, which we denote as \( m_1 \) and \( m_2 \). ### Step 3: Use the relationship of slopes We are given that the slopes are in the ratio \( 3:1 \). Therefore, we can express this relationship as: \[ m_1 = 3m_2 \] ### Step 4: Sum of the slopes From the properties of quadratic equations, the sum of the roots (slopes) is given by: \[ m_1 + m_2 = -\frac{2h}{a} \] Substituting \( m_1 = 3m_2 \) into the equation: \[ 3m_2 + m_2 = -\frac{2h}{a} \] This simplifies to: \[ 4m_2 = -\frac{2h}{a} \] ### Step 5: Solve for \( m_2 \) From the above equation, we can solve for \( m_2 \): \[ m_2 = -\frac{h}{2a} \] ### Step 6: Product of the slopes The product of the slopes \( m_1 \cdot m_2 \) is given by: \[ m_1 m_2 = \frac{b}{a} \] Substituting \( m_1 = 3m_2 \): \[ 3m_2 \cdot m_2 = \frac{b}{a} \] This leads to: \[ 3m_2^2 = \frac{b}{a} \] ### Step 7: Substitute \( m_2 \) Now substituting \( m_2 = -\frac{h}{2a} \) into the equation: \[ 3\left(-\frac{h}{2a}\right)^2 = \frac{b}{a} \] This simplifies to: \[ 3 \cdot \frac{h^2}{4a^2} = \frac{b}{a} \] ### Step 8: Rearranging the equation Multiplying both sides by \( 4a^2 \): \[ 3h^2 = 4ab \] ### Step 9: Solve for \( h^2 \) Finally, we can solve for \( h^2 \): \[ h^2 = \frac{4ab}{3} \] ### Final Answer Thus, the value of \( h^2 \) is: \[ \boxed{\frac{4ab}{3}} \]

To solve the problem, we start with the equation of the pair of straight lines given by: \[ ax^2 + 2hxy + by^2 = 0 \] We need to find \( h^2 \) given that the slopes of the lines are in the ratio \( 3:1 \). ### Step 1: Rewrite the equation We can rewrite the equation by dividing through by \( x^2 \): ...
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OBJECTIVE RD SHARMA ENGLISH-PAIR OF STRAIGHT LINES-Chapter Test
  1. If the slopes of the lines given by ax^(2)+2hxy+by^(2)=0 are in the ra...

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  2. If the lines given by ax^(2)+2hxy+by^(2)=0 are equally inclined to the...

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  3. The equation to the striaght lines passing through the origin and maki...

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  4. Prove that the limiting points of the system x^(2)+y^(2)+2gx+c+lamda(x...

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  5. If the area of the triangle formed by the pair of lines 8x^2 - 6xy + y...

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  6. The equation to the pair of straight lines bisecting the angles betwe...

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  7. If the pair of lines sqrt(3)x^2-4x y+sqrt(3)y^2=0 is rotated about the...

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  8. Show that if two of the lines ax^3+bx^2y+cxy^2+dy^3=0 (a ne 0) make co...

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  9. If the pairs of straight lines ax^2+2hxy-ay^2=0 and bx^2+2gxy-by^2=0 b...

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  10. The equation a^2x^2+2h(a+b)x y+b^2y^2=0 and a x^2+2h x y+b y^2=0 repre...

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  11. If (x^(2))/(a) + (y^(2))/(b) + (2xy)/(h) =0 represent pair of straig...

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  12. If the lines represented by the equation ax^(2)+2hxy+by^(2)+2gx+2fy+c=...

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  13. The distance between the two lines represented by the  sides of an equ...

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  14. The equation of the image of the lines y=|x| in the line mirror x = 2 ...

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  15. If the equation 3x^(2)+xy-y^(2)-3x+6y+k=0 represents a pair of straigh...

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  16. The equation of second degree x^2+2sqrt2xy+2y^2+4x+4sqrt2y+1=0 represe...

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  17. The value of lambda for which the equation x^2-y^2 - x - lambda y - ...

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  18. Distance between the pair of lines represented by the equation x^(2)-6...

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  19. The equation x^2 - 3xy+ lambday^2 + 3x - 5y + 2 = 0 where lambda is a ...

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