The two lines represented by `3a x^2+5x y+(a^2-2)y^2=0` are perpendicular to each other for two values of `a` (b) a for one value of `a` (d) for no values of `a`

Options

A. two values of a
B. for one value of a
C. for one value of a
D. for no value of a

Answer

A

Explanation

The pair of lines represented by the given equation will be perpendicular to each other, if
`"Coefficient of "x^(2)+"Coefficient of "y^(2)=0`
`rArr" "3a+a^(2)-2=0rArra=(-3pmsqrt(9+8))/(2)=(-3pmsqrt(17))/(2)`
Thus, there are two values of a for which the lines represented by `2x^(2)-7xy+3y^(2)=0,` is