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Statement-1: If a, b are non-zero real n...

Statement-1: If a, b are non-zero real number such that `a+b=2`, then `ax^(2)+2xy+by^(2)+2ax+2by=0` represents a pair of straight lines. Statement-2: If a, b are of opposite signs, then `ax^(2)+2xt+by^(2)=0` represents a pair of distinct lines passing through the origin.

A

Statement-1 is True, Statement-2 is True, Statement-2 is a correct explanation for Statement-1.

B

Statement-1 is True, Statement-2 is True, Statement-2 is not a correct explanation for Statement-1.

C

Statement-1 is True, Statement-2 is False.

D

Statement-1 is False, Statement-2 is True.

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem, we need to analyze both statements and determine their validity. ### Step 1: Analyze Statement 1 Statement 1 claims that if \( a, b \) are non-zero real numbers such that \( a + b = 2 \), then the equation \[ ax^2 + 2hxy + by^2 + 2ax + 2by = 0 \] represents a pair of straight lines. #### Step 1.1: Identify the coefficients The general form of the equation of a pair of straight lines is given by: \[ Ax^2 + 2Hxy + By^2 + 2Gx + 2Fy + C = 0 \] From the given equation, we can identify: - \( A = a \) - \( H = 1 \) (since \( 2h = 2 \)) - \( B = b \) - \( G = a \) - \( F = b \) - \( C = 0 \) #### Step 1.2: Apply the condition for a pair of straight lines The condition for the equation to represent a pair of straight lines is given by: \[ ABC + 2FGH - AF^2 - BG^2 - CH^2 = 0 \] Substituting the identified coefficients into this condition, we get: \[ a \cdot b \cdot 0 + 2 \cdot b \cdot a \cdot 1 - a \cdot b^2 - b \cdot a^2 - 0 \cdot 1^2 = 0 \] This simplifies to: \[ 2ab - ab^2 - a^2b = 0 \] #### Step 1.3: Factor the equation Factoring out \( ab \): \[ ab(2 - a - b) = 0 \] Since \( a \) and \( b \) are non-zero, we have: \[ 2 - a - b = 0 \quad \Rightarrow \quad a + b = 2 \] Thus, Statement 1 is **true**. ### Step 2: Analyze Statement 2 Statement 2 claims that if \( a, b \) are of opposite signs, then the equation \[ ax^2 + 2xy + by^2 = 0 \] represents a pair of distinct lines passing through the origin. #### Step 2.1: Identify the coefficients In this case, we have: - \( A = a \) - \( H = 1 \) - \( B = b \) - \( G = 0 \) - \( F = 0 \) - \( C = 0 \) #### Step 2.2: Apply the condition for distinct lines For the equation to represent distinct lines, the condition is: \[ 1 - ab > 0 \] Since \( a \) and \( b \) are of opposite signs, \( ab < 0 \). Therefore, we have: \[ 1 - ab > 1 > 0 \] This means that the condition is satisfied, and the equation represents distinct lines passing through the origin. Thus, Statement 2 is also **true**. ### Conclusion Both statements are true, but Statement 2 does not provide a correct explanation for Statement 1. Therefore, the answer is that both statements are true, but Statement 2 is not a correct explanation for Statement 1.

To solve the problem, we need to analyze both statements and determine their validity. ### Step 1: Analyze Statement 1 Statement 1 claims that if \( a, b \) are non-zero real numbers such that \( a + b = 2 \), then the equation \[ ax^2 + 2hxy + by^2 + 2ax + 2by = 0 \] ...
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