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Draw a graph of the function y=[x]+|1-x|...

Draw a graph of the function `y=[x]+|1-x|,-1lexle3`. Determine the points if any where this function is not differentiable.

A

`(-1,0,1,2,3)`

B

`(-1,0,2)`

C

`(0,1,2,3)`

D

`(-1,0,1,2)`

Text Solution

Verified by Experts

The correct Answer is:
C

We have
`f(x)={{:(,-x,-1 lexlt0),(,1-x,0lexlt1),(,x,1lexlt2),(,1+x,2lexlt3),(,5,x=3):}`
Clearly, f(x) is discontinuous at x=0,1,2 and 3.
So, it is not differentiable at these points.
At x=-1, we have
`underset(x to 1^(+))lim f(x)=underset(x to 1^(+))lim-x=1=f(-1)`
So, it is continuous at x=-1
Also, (RHD at x=1)=-1 (a finite number).
Therefore, f(x) is differentiable at x=-1
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