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f(x)=(1)/(1-x)and f^(n)=fofof....of, the...

`f(x)=(1)/(1-x)and f^(n)=fofof....of`, then the points of discontinuitym of f^(3n)(x) is/are

A

x=2

B

x=0,1

C

x=1,2

D

none of these

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To solve the problem, we need to analyze the function \( f(x) = \frac{1}{1-x} \) and determine the points of discontinuity for the function \( f^{(3n)}(x) \), which represents the function \( f \) composed with itself \( 3n \) times. ### Step 1: Identify the points of discontinuity of \( f(x) \) The function \( f(x) = \frac{1}{1-x} \) is defined for all \( x \) except where the denominator is zero. Therefore, we set the denominator equal to zero to find the points of discontinuity: \[ 1 - x = 0 \implies x = 1 \] Thus, \( f(x) \) is discontinuous at \( x = 1 \). ### Step 2: Determine the behavior of \( f(x) \) Next, we analyze the behavior of \( f(x) \) as \( x \) approaches the point of discontinuity: - As \( x \) approaches \( 1 \) from the left (\( x \to 1^- \)), \( f(x) \to +\infty \). - As \( x \) approaches \( 1 \) from the right (\( x \to 1^+ \)), \( f(x) \to -\infty \). This confirms that \( x = 1 \) is indeed a point of discontinuity. ### Step 3: Find \( f^{(2)}(x) \) Now, we will find \( f^{(2)}(x) = f(f(x)) \): \[ f^{(2)}(x) = f\left(f(x)\right) = f\left(\frac{1}{1-x}\right) \] Calculating \( f\left(\frac{1}{1-x}\right) \): \[ f\left(\frac{1}{1-x}\right) = \frac{1}{1 - \frac{1}{1-x}} = \frac{1}{\frac{(1-x)-1}{1-x}} = \frac{1-x}{-x} = \frac{x-1}{x} \] ### Step 4: Identify points of discontinuity of \( f^{(2)}(x) \) Now, we need to find the points of discontinuity of \( f^{(2)}(x) = \frac{x-1}{x} \): The function \( \frac{x-1}{x} \) is discontinuous where the denominator is zero: \[ x = 0 \] Thus, \( f^{(2)}(x) \) is discontinuous at \( x = 0 \). ### Step 5: Find \( f^{(3)}(x) \) Next, we find \( f^{(3)}(x) = f(f^{(2)}(x)) = f\left(\frac{x-1}{x}\right) \): Calculating \( f\left(\frac{x-1}{x}\right) \): \[ f\left(\frac{x-1}{x}\right) = \frac{1}{1 - \frac{x-1}{x}} = \frac{1}{\frac{x - (x-1)}{x}} = \frac{1}{\frac{1}{x}} = x \] ### Step 6: Identify points of discontinuity of \( f^{(3)}(x) \) The function \( f^{(3)}(x) = x \) is continuous for all \( x \). Therefore, it does not introduce any new points of discontinuity. ### Step 7: Generalize to \( f^{(3n)}(x) \) Since \( f^{(3)}(x) = x \) is continuous, we can conclude that \( f^{(3n)}(x) \) for any integer \( n \) will also be continuous. ### Conclusion The only point of discontinuity for \( f^{(3n)}(x) \) is at \( x = 1 \) from the first iteration of \( f(x) \). Thus, the points of discontinuity of \( f^{(3n)}(x) \) are: \[ \text{Points of discontinuity: } x = 1 \]

To solve the problem, we need to analyze the function \( f(x) = \frac{1}{1-x} \) and determine the points of discontinuity for the function \( f^{(3n)}(x) \), which represents the function \( f \) composed with itself \( 3n \) times. ### Step 1: Identify the points of discontinuity of \( f(x) \) The function \( f(x) = \frac{1}{1-x} \) is defined for all \( x \) except where the denominator is zero. Therefore, we set the denominator equal to zero to find the points of discontinuity: \[ 1 - x = 0 \implies x = 1 ...
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