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If f(x)=[sin^(2) x] ([.] denotes the gre...

If `f(x)=[sin^(2) x]` ([.] denotes the greatest integer function), then

A

f is everywhere continuous

B

f is everywhere differerntiable

C

f is a constant function

D

none of these

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The correct Answer is:
To solve the problem, we need to analyze the function \( f(x) = [\sin^2 x] \), where \([.]\) denotes the greatest integer function. ### Step-by-step Solution: 1. **Understanding the Function**: The function \( f(x) = [\sin^2 x] \) takes the value of \( \sin^2 x \) and applies the greatest integer function to it. The sine function oscillates between -1 and 1, so \( \sin^2 x \) will oscillate between 0 and 1. 2. **Range of \( \sin^2 x \)**: The maximum value of \( \sin^2 x \) is 1 (when \( \sin x = 1 \)), and the minimum value is 0 (when \( \sin x = 0 \)). Therefore, the range of \( \sin^2 x \) is [0, 1]. 3. **Applying the Greatest Integer Function**: - For \( 0 \leq \sin^2 x < 1 \), \( [\sin^2 x] = 0 \). - For \( \sin^2 x = 1 \), \( [\sin^2 x] = 1 \). The value of \( f(x) \) will be: - \( f(x) = 0 \) for all \( x \) except at points where \( \sin^2 x = 1 \) (which occurs at odd multiples of \( \frac{\pi}{2} \)). - \( f(x) = 1 \) at \( x = \frac{\pi}{2} + n\pi \) for \( n \in \mathbb{Z} \). 4. **Identifying Points of Discontinuity**: The function \( f(x) \) is discontinuous at points where \( \sin^2 x = 1 \) (i.e., \( x = \frac{\pi}{2} + n\pi \)). At these points: - The left-hand limit and right-hand limit of \( f(x) \) are both 0. - The value of \( f(x) \) at these points is 1. Therefore, \( f(x) \) is discontinuous at these points. 5. **Continuity and Differentiability**: - Since \( f(x) \) is discontinuous at infinitely many points, it cannot be continuous everywhere. - A function must be continuous at a point to be differentiable there. Therefore, \( f(x) \) is not differentiable anywhere. 6. **Conclusion**: - \( f(x) \) is not everywhere continuous (Option A is false). - \( f(x) \) is not everywhere differentiable (Option B is false). - \( f(x) \) is not a constant function (Option C is false). - Thus, the correct answer is Option D: None of these.

To solve the problem, we need to analyze the function \( f(x) = [\sin^2 x] \), where \([.]\) denotes the greatest integer function. ### Step-by-step Solution: 1. **Understanding the Function**: The function \( f(x) = [\sin^2 x] \) takes the value of \( \sin^2 x \) and applies the greatest integer function to it. The sine function oscillates between -1 and 1, so \( \sin^2 x \) will oscillate between 0 and 1. 2. **Range of \( \sin^2 x \)**: ...
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OBJECTIVE RD SHARMA ENGLISH-CONTINUITY AND DIFFERENTIABILITY-Section I - Solved Mcqs
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