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Statement-1: The function f(x)=[x]+x^(2)...

Statement-1: The function `f(x)=[x]+x^(2)` is discontinuous at all integer points.
Statement-2: The function g(x)=[x] has Z as the set of points of its discontinuous from left.

A

1

B

2

C

3

D

4

Text Solution

AI Generated Solution

The correct Answer is:
To analyze the statements given in the question, we will evaluate each statement step by step. ### Step 1: Evaluate Statement-2 The function \( g(x) = [x] \) is the greatest integer function, which returns the largest integer less than or equal to \( x \). **Discontinuity of \( g(x) \):** - The function \( g(x) \) is discontinuous at every integer point. This is because as \( x \) approaches an integer \( n \) from the left (i.e., \( n - 0.1, n - 0.01, \ldots \)), \( g(x) \) will return \( n - 1 \). - However, at \( x = n \), \( g(n) = n \). Thus, there is a jump in the function value at every integer point. **Conclusion for Statement-2:** - Therefore, Statement-2 is correct: \( g(x) \) has \( \mathbb{Z} \) (the set of integers) as the set of points of its discontinuity from the left. ### Step 2: Evaluate Statement-1 The function \( f(x) = [x] + x^2 \) consists of two parts: the greatest integer function \( [x] \) and the continuous function \( x^2 \). **Discontinuity of \( f(x) \):** - Since \( [x] \) is discontinuous at every integer point, we need to check if the sum \( f(x) = [x] + x^2 \) is also discontinuous at those points. - At an integer point \( n \): - As \( x \) approaches \( n \) from the left, \( f(n - \epsilon) = [n - \epsilon] + (n - \epsilon)^2 = n - 1 + (n - \epsilon)^2 \). - As \( x \) approaches \( n \) from the right, \( f(n + \epsilon) = [n + \epsilon] + (n + \epsilon)^2 = n + (n + \epsilon)^2 \). **Limit Analysis:** - The left-hand limit as \( x \to n \) is: \[ \lim_{x \to n^-} f(x) = n - 1 + n^2 - 2n\epsilon + \epsilon^2 \quad \text{(approaches } n^2 - n + 1\text{)} \] - The right-hand limit as \( x \to n \) is: \[ \lim_{x \to n^+} f(x) = n + n^2 + 2n\epsilon + \epsilon^2 \quad \text{(approaches } n^2 + n\text{)} \] Since the left-hand limit and right-hand limit at \( n \) are not equal, \( f(x) \) is discontinuous at every integer point. **Conclusion for Statement-1:** - Therefore, Statement-1 is also correct: the function \( f(x) = [x] + x^2 \) is discontinuous at all integer points. ### Final Conclusion Both statements are correct. ### Summary of Steps: 1. Analyze the discontinuity of \( g(x) = [x] \) at integer points. 2. Evaluate the function \( f(x) = [x] + x^2 \) and check its continuity at integer points. 3. Conclude that both statements are correct.

To analyze the statements given in the question, we will evaluate each statement step by step. ### Step 1: Evaluate Statement-2 The function \( g(x) = [x] \) is the greatest integer function, which returns the largest integer less than or equal to \( x \). **Discontinuity of \( g(x) \):** - The function \( g(x) \) is discontinuous at every integer point. This is because as \( x \) approaches an integer \( n \) from the left (i.e., \( n - 0.1, n - 0.01, \ldots \)), \( g(x) \) will return \( n - 1 \). - However, at \( x = n \), \( g(n) = n \). Thus, there is a jump in the function value at every integer point. ...
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