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Find the area bounded by the curve f(x)...

Find the area bounded by the curve `f(x)=x+ sin x and ` its inverse function between the ordinates `x=0" to "x=2pi`.

A

`4pi`

B

`8pi`

C

4

D

8

Text Solution

Verified by Experts

The correct Answer is:
d
Clearly, `f:[0,2pi]in[0,2pi]"given by f"(x)=x+sinx` is bijection. So its inverse exists. The graph of `f^(-1)(x)` is the mirror image of the graph of `f(x)` in the line `y=x.`

`therefore` Required area A is given by
A=4 (Area of one loop)
`impliesA=4[underset(0)overset(pi)(int)(x+sinx)dx-underset(0)overset(pi)(int)x dy]`
`impliesA=4underset(0)overset(pi)(int)sinxdx=-4[cosx]_(0)^(pi)`
`impliesA=-4[cospi-cos 0]=8` sq. units.
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OBJECTIVE RD SHARMA ENGLISH-AREAS OF BOUNDED REGIONS-Chapter Test
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  13. If area bounded by the curve y^(2)=4ax and y=mx is a^(2)//3 , then the...

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  14. The value of a for which the area between the curves y^(2) = 4ax and x...

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