The mean of first n odd natural numbers ...

The mean of first `n` odd natural numbers is `(n^2)/(81)` , then `n=` (a) 9 (b) 81 (c) 27 (d) 18

A

9

B

81

C

27

D

none of these

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The correct Answer is:

B

It is given that
`(1+3+5+7+ ... + (2n-1))/(n)=(n^(2))/(81) rArr (n^(2))/(n)=(n^(2))/(81) rArr n=81`

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