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The value of lim(xrarr 0) (1-cos(1-cos ...

The value of ` lim_(xrarr 0) (1-cos(1-cos x))/(x^4)` is equal to

A

`(1)(8)`

B

`(1)/(2)`

C

`(1)/(4)`

D

none of these

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AI Generated Solution

The correct Answer is:
To solve the limit \( \lim_{x \to 0} \frac{1 - \cos(1 - \cos x)}{x^4} \), we will follow these steps: ### Step 1: Identify the limit form First, we need to evaluate the limit as \( x \) approaches 0. We notice that both the numerator and denominator approach 0, which indicates that we have an indeterminate form of type \( \frac{0}{0} \). ### Step 2: Use the identity for cosine We can use the trigonometric identity for \( 1 - \cos y \): \[ 1 - \cos y \approx \frac{y^2}{2} \quad \text{as } y \to 0. \] Here, we will set \( y = 1 - \cos x \). ### Step 3: Find \( 1 - \cos x \) as \( x \to 0 \) Using the same identity, we find: \[ 1 - \cos x \approx \frac{x^2}{2} \quad \text{as } x \to 0. \] Thus, as \( x \to 0 \): \[ y = 1 - \cos x \approx \frac{x^2}{2}. \] ### Step 4: Substitute \( y \) into the limit Now substituting \( y \) into our limit: \[ \lim_{x \to 0} \frac{1 - \cos(1 - \cos x)}{x^4} = \lim_{x \to 0} \frac{1 - \cos\left(\frac{x^2}{2}\right)}{x^4}. \] ### Step 5: Apply the cosine identity again Now, we apply the cosine identity again: \[ 1 - \cos\left(\frac{x^2}{2}\right) \approx \frac{\left(\frac{x^2}{2}\right)^2}{2} = \frac{x^4}{8} \quad \text{as } x \to 0. \] ### Step 6: Substitute back into the limit Now substituting this back into our limit: \[ \lim_{x \to 0} \frac{\frac{x^4}{8}}{x^4} = \lim_{x \to 0} \frac{1}{8} = \frac{1}{8}. \] ### Final Answer Thus, the value of the limit is: \[ \boxed{\frac{1}{8}}. \]
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OBJECTIVE RD SHARMA ENGLISH-LIMITS-Exercise
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  2. Evaluate the following limits (i) lim(x to (pi)/(2)) tan^(2) x [sqr...

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  3. The value of lim(xrarr 0) (1-cos(1-cos x))/(x^4) is equal to

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  4. The value of lim (xto0) (cos (sin x )- cos x)/(x ^(4)) is equal to :

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  5. The value of underset(xto1)lim(2-x)^(tan((pix)/(2))) is

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  6. The value of lim(xrarroo) ((3x-4)/(3x+2))^(((x+1)/3)) is

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  7. lim(x->oo) ((x^2-2x+1)/(x^2-4x+2))^x is equal to

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  8. The value of lim(xrarr0) ((1+tanx)/(1+sin x))^(cosec x) , is

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  9. lim(x rarr 0)((5x^2+1)/(3x^2+1))^(1//x^2)

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  10. Evaluate: ("lim")(n→oo)x[tan^(-1)((x+1)/(x+2))-tan^(-1)(x/(x+2))]

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  11. The value of lim(x->0) ( int0 ^ (x^2) cost^2 dt)/( xsin x) is

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  12. ("lim")(xvec0)(1n(1+2h)-21 n(1+h))/(h^2)=

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  13. The value of lim(xrarr1)(log5 5x)^(logx5) , is

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  14. The value of lim(xrarr1)(log2 2x)^(logx5), is

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  15. lim(x->0) (sinx^n)/((sinx)^m),(mltn), is equal to (a) 1 (b) 0 (c) n...

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  16. If 0lt xlty, then lim(xrarroo) (y^n+x^n)^(1//n) is equal to

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  17. Evaluate the limit: ("lim")(xvecoo)[sqrt(a^2x^2+a x+1)-sqrt(a^2x^2+1)]

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  18. lim(xrarr1)(1-x)tan((pix)/2) is equal to

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  19. The value of lim(xrarr0) (x(5^x-1))/(1-cos x), is

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  20. Evaluate underset(xto2)limsin(e^(x-2)-1)/(log(x-1))

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