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The domain of definition of the function...

The domain of definition of the function `f(X)=x^(log_(10)x`, is

A

`(0,1) cup (1,oo)`

B

`(0,oo)`

C

`[1,oo)`

D

`[0,1) cup (1,oo)`

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The correct Answer is:
To find the domain of the function \( f(x) = x^{\log_{10} x} \), we need to determine the values of \( x \) for which this function is defined. ### Step-by-Step Solution: 1. **Understanding the Function**: The function is defined as \( f(x) = x^{\log_{10} x} \). This involves both the base \( x \) and the exponent \( \log_{10} x \). 2. **Conditions for the Base**: The base \( x \) must be positive because the logarithm function \( \log_{10} x \) is only defined for \( x > 0 \). Therefore, we have: \[ x > 0 \] 3. **Conditions for the Exponent**: The exponent \( \log_{10} x \) must also be defined. Since \( \log_{10} x \) is defined for \( x > 0 \), we already satisfy this condition with our previous step. 4. **Exclusion of Specific Values**: We also need to consider if there are any specific values of \( x \) that could cause issues with the function. The expression \( x^{\log_{10} x} \) is well-defined as long as \( x \neq 1 \) because: - If \( x = 1 \), then \( \log_{10} 1 = 0 \) and \( 1^0 = 1 \), which is defined but does not contribute to the exponential nature of the function. - However, since we are looking for a domain where the function behaves like an exponential function, we exclude \( x = 1 \). 5. **Conclusion**: Therefore, the domain of the function \( f(x) = x^{\log_{10} x} \) is: \[ x > 0 \quad \text{and} \quad x \neq 1 \] This can be expressed in interval notation as: \[ (0, 1) \cup (1, \infty) \] ### Final Answer: The domain of the function \( f(x) = x^{\log_{10} x} \) is \( (0, 1) \cup (1, \infty) \).
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OBJECTIVE RD SHARMA ENGLISH-REAL FUNCTIONS -Exercise
  1. The domain of definition of f(x)=log(3)|log(e)x|, is

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  2. The domain of definition of the function f(x)=log(3){-log(4)((6x-4)...

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  3. The domain of definition of the function f(X)=x^(log(10)x, is

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  4. The domain of the function f(x)=(1)/(sqrt(|cosx|+cosx)) is

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  5. If the function f(x)=log(x-2)-log(x-3) and g(x)=log((x-2)/(x-3)) are i...

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  6. The domain of definition of the function f(x)=sin^(-1)((4)/(3+2 cos x)...

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  7. The domain of the function f(x)=cos^(-1)[secx], where [x] denotes the ...

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  8. Let f be a real vlaued fuction with domain R such that f(x+1)+f(x-1)=s...

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  9. Let f be a real valued function with domain R satisfying f(x + k) =1+[...

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  10. The function f(x) given by f(x)=(sin 8x cos x-sin6x cos 3x)/(cos x cos...

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  11. If f(x) and g(x) are two real functions such that f(x)+g(x)=e^(x) and ...

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  12. Let f(x)=|x-2|+|x-3|+|x-4| and g(x)=f(x+1). Then :

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  13. If T(1) is the period of the function f(x)=e^(3(x-[x])) and T(2) is th...

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  14. Find the range of f(x)=sqrt(cos(sinx))+sqrt(sin(cosx)).

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  15. Find the domain of the function: f(x)=(sin^(-1)(x-3))/(sqrt(9-x^2))

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  16. If f: RvecR and g: RvecR are defined by f(x)=2x+3a n dg(x)=x^2+7, then...

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  17. Suppose f:[-2,2] to R is defined by f(x)={{:(-1 " for " -2 le x le 0...

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  18. If f:R->R and g:R->R is given by f(x) =|x| and g(x)=[x] for each x in ...

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  19. If a , b are two fixed positive integers such that f(a+x)=b+[b^3+1-3b^...

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  20. The domain of the function f(x)=(log)(3+x)(x^2-1) is (-3,-1)uu(1,oo) ...

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