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If cos(theta-alpha)=a and cos(theta-beta...

If `cos(theta-alpha)=a` and `cos(theta-beta)=b` then the value of `sin^(2)(alpha-beta)+2ab cos(alpha-beta)`.

A

`a^(2)+b^(2)`

B

`a^(2)-b^(2)`

C

`b^(2)-a^(2)`

D

`-a^(2)-b^(2)`

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