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If cosx-sinalphacotbetasinx=cosa , then ...

If `cosx-sinalphacotbetasinx=cosa ,` then the value of `tan(x/2)` is `-tan(alpha/2)cot(beta/2)` (b) `tan(alpha/2)tan(beta/2)` `-cot((alphabeta)/2)tan(beta/2)` (d) `cot(alpha/2)cot(beta/2)`

A

`cot""(alpha)/(2)tan""(beta)/(2)`

B

`-tan""(alpha)/(2)cot""(beta)/(2)`

C

`-tan""(alpha)/(2)tan""(beta)/(2)`

D

`cot""(alpha)/(2)cot""(beta)/(2)`

Text Solution

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The correct Answer is:
B
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