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The value of sin12^(@)sin24^(@)sin48^(@)...

The value of `sin12^(@)sin24^(@)sin48^(@)sin84^(@),` is

A

`cos20^(@)cos40^(@)cos60^(@)cos80^(@)`

B

1/16

C

`sin20^(@)sin40^(@)sin60^(@)sin80^(@)`

D

`3//15`

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AI Generated Solution

The correct Answer is:
To find the value of \( \sin 12^\circ \sin 24^\circ \sin 48^\circ \sin 84^\circ \), we can use trigonometric identities and properties. Let's break it down step by step. ### Step 1: Rewrite the Expression We start with: \[ \sin 12^\circ \sin 24^\circ \sin 48^\circ \sin 84^\circ \] We can multiply and divide the expression by 4: \[ = \frac{1}{4} \cdot 4 \sin 12^\circ \sin 24^\circ \sin 48^\circ \sin 84^\circ \] ### Step 2: Pair the Sine Functions We can pair the sine functions: \[ = \frac{1}{4} \cdot (2 \sin 12^\circ \sin 48^\circ) \cdot (2 \sin 24^\circ \sin 84^\circ) \] ### Step 3: Use the Product-to-Sum Formulas Using the identity \( 2 \sin A \sin B = \cos(A - B) - \cos(A + B) \): 1. For \( 2 \sin 12^\circ \sin 48^\circ \): \[ 2 \sin 12^\circ \sin 48^\circ = \cos(48^\circ - 12^\circ) - \cos(48^\circ + 12^\circ) = \cos 36^\circ - \cos 60^\circ \] 2. For \( 2 \sin 24^\circ \sin 84^\circ \): \[ 2 \sin 24^\circ \sin 84^\circ = \cos(84^\circ - 24^\circ) - \cos(84^\circ + 24^\circ) = \cos 60^\circ - \cos 108^\circ \] ### Step 4: Substitute Back into the Expression Substituting these back, we have: \[ = \frac{1}{4} \left( \cos 36^\circ - \cos 60^\circ \right) \left( \cos 60^\circ - \cos 108^\circ \right) \] ### Step 5: Evaluate the Cosine Values We know: - \( \cos 60^\circ = \frac{1}{2} \) - \( \cos 108^\circ = -\sin 18^\circ = -\frac{\sqrt{5}-1}{4} \) (since \( \cos 108^\circ = \cos(90^\circ + 18^\circ) = -\sin 18^\circ \)) - \( \cos 36^\circ = \frac{\sqrt{5}+1}{4} \) ### Step 6: Substitute and Simplify Now substituting these values: \[ = \frac{1}{4} \left( \frac{\sqrt{5}+1}{4} - \frac{1}{2} \right) \left( \frac{1}{2} - \left(-\frac{\sqrt{5}-1}{4}\right) \right) \] ### Step 7: Simplify Each Part 1. Simplifying \( \frac{\sqrt{5}+1}{4} - \frac{1}{2} \): \[ = \frac{\sqrt{5}+1 - 2}{4} = \frac{\sqrt{5}-1}{4} \] 2. Simplifying \( \frac{1}{2} + \frac{\sqrt{5}-1}{4} \): \[ = \frac{2}{4} + \frac{\sqrt{5}-1}{4} = \frac{2 + \sqrt{5} - 1}{4} = \frac{\sqrt{5}+1}{4} \] ### Step 8: Combine the Results Now we combine: \[ = \frac{1}{4} \cdot \frac{\sqrt{5}-1}{4} \cdot \frac{\sqrt{5}+1}{4} \] This can be simplified using the difference of squares: \[ = \frac{1}{4} \cdot \frac{(\sqrt{5})^2 - (1)^2}{16} = \frac{1}{4} \cdot \frac{5 - 1}{16} = \frac{1}{4} \cdot \frac{4}{16} = \frac{1}{16} \] ### Final Result Thus, the value of \( \sin 12^\circ \sin 24^\circ \sin 48^\circ \sin 84^\circ \) is: \[ \boxed{\frac{1}{16}} \]
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