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Prove that the angle between the tangent...

Prove that the angle between the tangents from `(alpha,beta)` to the circle `x^2+y^2=a^2` is `2tan^(-1)(a/(sqrt(S_1)))` , where `S_1=alpha^2+beta^2-a^2`

A

`tan^(-1)((a)/(sqrt(S_(1))))`

B

`2tan^(-1)((a)/(sqrt(S_(1))))`

C

`2 tan^(-1)((sqrt(S_(1)))/(a))`

D

none of these

Text Solution

Verified by Experts

The correct Answer is:
B

Let PT and PT' be the tangents drawn from `P(alpha, beta)` to the circle `x^(2)+y^(2)=a^(2)`, and let `angleTPT'=theta.` If O is the centre of the circle, then
`angleTPO=angleT'PO=theta//2`
`:. tan. (theta)/(2)=(OT)/(OP)=(a)/(sqrt(S_(1)))rArr theta = 2 tan^(-1)((a)/(sqrt(S_(1)))`
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