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The equation (x^2 - a^2)^2 + (y^2 - b^2)...

The equation `(x^2 - a^2)^2 + (y^2 - b^2)^2 = 0` represents points

A

which are collinear

B

which lie on a circle with centre at (0, 0)

C

which lie on a circle with centre at (a, b)

D

none of these

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The correct Answer is:
To solve the equation \((x^2 - a^2)^2 + (y^2 - b^2)^2 = 0\) and determine the points it represents, we can follow these steps: ### Step 1: Analyze the equation The given equation is \((x^2 - a^2)^2 + (y^2 - b^2)^2 = 0\). Since both terms are squares, the only way their sum can equal zero is if each term is individually equal to zero.

To solve the equation \((x^2 - a^2)^2 + (y^2 - b^2)^2 = 0\) and determine the points it represents, we can follow these steps: ### Step 1: Analyze the equation The given equation is \((x^2 - a^2)^2 + (y^2 - b^2)^2 = 0\). Since both terms are squares, the only way their sum can equal zero is if each term is individually equal to zero.
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OBJECTIVE RD SHARMA ENGLISH-CIRCLES-Section I - Solved Mcqs
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