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If two circles and a(x^2 +y^2)+bx + cy =...

If two circles and `a(x^2 +y^2)+bx + cy =0` and `p(x^2+y^2)+qx+ry= 0` touch each other, then

A

aC=cA

B

bC=cB

C

aB=bA

D

a A=bB=cC

Text Solution

Verified by Experts

The correct Answer is:
B
Clearly both are circles pass through the origin. The two circles will touch each other if they have a common tangent at the origin. The tangents at the origin to the two circles are bx+cy=0 and Bx+Cy=0. These two must be identical
`:. (b)/(B)=(c)/(C)rArr bC=Bc`
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