Home
Class 12
MATHS
If circles x^(2)+y^(2)+2x+2y+c=0 and x^(...

If circles `x^(2)+y^(2)+2x+2y+c=0` and `x^(2)+y^(2)+2ax+2ay+c=0` where `c in R^(+), a != 1` are such that one circle lies inside the other, then

A

`a in (0, sqrt((c)/(2)))-{1}`

B

`a in (- sqrt((c)/(2)),sqrt((c)/(2)))-{1}`

C

` a in (-sqrt((c)/(2)),0)`

D

none of these

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem, we need to analyze the given circles and determine the conditions under which one circle lies inside the other. ### Step 1: Write the equations of the circles The equations of the circles are: 1. Circle 1: \( x^2 + y^2 + 2x + 2y + c = 0 \) 2. Circle 2: \( x^2 + y^2 + 2ax + 2ay + c = 0 \) ### Step 2: Rewrite the equations in standard form We can rewrite both equations in the standard form of a circle \((x - h)^2 + (y - k)^2 = r^2\). For Circle 1: \[ x^2 + y^2 + 2x + 2y + c = 0 \implies (x + 1)^2 + (y + 1)^2 = 1 - c \] Thus, the center \(C_1\) is \((-1, -1)\) and radius \(r_1 = \sqrt{1 - c}\). For Circle 2: \[ x^2 + y^2 + 2ax + 2ay + c = 0 \implies (x + a)^2 + (y + a)^2 = 1 - c \] Thus, the center \(C_2\) is \((-a, -a)\) and radius \(r_2 = \sqrt{1 - c}\). ### Step 3: Determine the conditions for one circle to lie inside the other For one circle to lie inside the other, the following conditions must be satisfied: 1. The distance between the centers must be less than the difference of the radii. 2. The circles must be on the same side of the radical axis. ### Step 4: Find the distance between the centers The distance \(d\) between the centers \(C_1\) and \(C_2\) is given by: \[ d = \sqrt{((-1) - (-a))^2 + ((-1) - (-a))^2} = \sqrt{(a - 1)^2 + (a - 1)^2} = \sqrt{2(a - 1)^2} = \sqrt{2} |a - 1| \] ### Step 5: Set up the inequality for one circle to lie inside the other For Circle 1 to lie inside Circle 2: \[ d < r_2 - r_1 \] This leads to: \[ \sqrt{2} |a - 1| < \sqrt{1 - c} - \sqrt{1 - c} \] This simplifies to: \[ \sqrt{2} |a - 1| < 0 \] This is not possible unless \(c\) is such that the circles do not intersect. ### Step 6: Analyze the conditions Since \(c\) is a positive real number, we can conclude that: 1. \(a > 0\) (from the product of the centers being positive). 2. The circles must not intersect, which leads to \(c < 1\). ### Conclusion Thus, the conditions for one circle to lie inside the other are: - \(c < 1\) - \(a > 0\)

To solve the problem, we need to analyze the given circles and determine the conditions under which one circle lies inside the other. ### Step 1: Write the equations of the circles The equations of the circles are: 1. Circle 1: \( x^2 + y^2 + 2x + 2y + c = 0 \) 2. Circle 2: \( x^2 + y^2 + 2ax + 2ay + c = 0 \) ### Step 2: Rewrite the equations in standard form ...
Promotional Banner

Topper's Solved these Questions

  • CIRCLES

    OBJECTIVE RD SHARMA ENGLISH|Exercise Section-I (Solved MCQs)|1 Videos
  • CIRCLES

    OBJECTIVE RD SHARMA ENGLISH|Exercise Section II - Assertion Reason Type|12 Videos
  • CIRCLES

    OBJECTIVE RD SHARMA ENGLISH|Exercise Chapter Test|53 Videos
  • CARTESIAN PRODUCT OF SETS AND RELATIONS

    OBJECTIVE RD SHARMA ENGLISH|Exercise Chapter Test|30 Videos
  • COMPLEX NUMBERS

    OBJECTIVE RD SHARMA ENGLISH|Exercise Chapter Test|58 Videos

Similar Questions

Explore conceptually related problems

The circles x^(2)+y^(2)+2x-2y+1=0 and x^(2)+y^(2)-2x-2y+1=0 touch each other

Two circles x^(2) + y^(2) + ax + ay - 7 = 0 and x^(2) + y^(2) - 10x + 2ay + 1 = 0 will cut orthogonally if the value of a is

If one of the circles x^2+y^2+2ax+c=0 and x^2+y^2+2bx+c=0 lies within the other, then

The two circles x^(2)+y^(2)=ax, x^(2)+y^(2)=c^(2) (c gt 0) touch each other if

The circle x^(2)+y^(2)-2ax-2ay+a^(2)=0 touches axes of co ordinates at

The two circles x^(2)+y^(2)=ax and x^(2)+y^(2)=c^(2)(c gt 0) touch each other, if |(c )/(a )| is equal to

For the circle x^(2)+y^(2)-4x+2y+c=0 radius is 4 then c=

Consider circles C_(1): x^(2) +y^(2) +2x - 2y +p = 0 C_(2): x^(2) +y^(2) - 2x +2y - p = 0 C_(3): x^(2) +y^(2) = p^(2) Statement-I: If the circle C_(3) intersects C_(1) orthogonally then C_(2) does not represent a circle Statement-II: If the circle C_(3) intersects C_(2) orthogonally then C_(2) and C_(3) have equal radii Then which of the following is true?

Consider the circles x^2+(y-1)^2=9,(x-1)^2+y^2=25. They are such that these circles touch each other one of these circles lies entirely inside the other each of these circles lies outside the other they intersect at two points.

If two circles x^2 + y^2 + ax + by = 0 and x^2 + y^2 + kx + ly = 0 touch each other, then (A) al = bk (B) ak = bl (C) ab = kl (D) none of these

OBJECTIVE RD SHARMA ENGLISH-CIRCLES-Section I - Solved Mcqs
  1. Consider four circles (x+-1)^2+(y+-1)^2=1 . Find the equation of the s...

    Text Solution

    |

  2. The radius of a circle is 20 cm. It is divided into four parts of e...

    Text Solution

    |

  3. If circles x^(2)+y^(2)+2x+2y+c=0 and x^(2)+y^(2)+2ax+2ay+c=0 where c i...

    Text Solution

    |

  4. A circle is passing through the points A (1, 1) and B (1, 3) and the b...

    Text Solution

    |

  5. The equation of a circle which touches the line y = x at (1 , 1) and ...

    Text Solution

    |

  6. The centres of a set of circles, each of radius 3, lie on the circle x...

    Text Solution

    |

  7. If the lines a1x+b1y+c1=0 and a2x+b2y+c2=0 cut the coordinae axes at c...

    Text Solution

    |

  8. Tangents drawn from the point P(1,8) to the circle x^(2)+y^(2)-6x-4y-1...

    Text Solution

    |

  9. A variable circle passes through the point A(a ,b) and touches the x-a...

    Text Solution

    |

  10. The centres of two circles C(1)andC(2) each of unit radius are at a di...

    Text Solution

    |

  11. Three distinct points A, B and C are given in the 2aedimensional coord...

    Text Solution

    |

  12. In DeltaABC, equation of side BC is x+y-6=0, also the circumcentre and...

    Text Solution

    |

  13. The locus of the mid-point of the chord of contact of tangents drawn f...

    Text Solution

    |

  14. A tangent PT is drawn to the circle x^(2)+y^(2)=4 at the point P( sqrt...

    Text Solution

    |

  15. A common tangent to the circles x^(2)+y^(2)=4 and (x-3)^(2)+y^(2)=1, i...

    Text Solution

    |

  16. If the line y=mx +1 meets the circle x^(2)+y^(2)+3x=0 in two points eq...

    Text Solution

    |

  17. If three distinct point A, B, C are given in the 2-dimensional coordi...

    Text Solution

    |

  18. about to only mathematics

    Text Solution

    |

  19. Tangents PA and PB are drawn to the circle x^2 +y^2=8 from any arbitra...

    Text Solution

    |

  20. Given two circles x^2 +y^2+3sqrt(2)(x+y)=0 and x^2 +y^2 +5sqrt(2)(x+y)...

    Text Solution

    |