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If the circle x^2 + y^2 = a^2 cuts off a...

If the circle `x^2 + y^2 = a^2` cuts off a chord of length `2b` from the line `y = mx +c`, then

A

`sqrt(a^(2)(a+m^(2))) lt c`

B

`sqrt(a^(2)(1-m^(2)))ltc`

C

`sqrt(a^(2)(a+m^(2))) gt c`

D

`sqrt(a^(2)(1-m^(2)))gtc`

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem step by step, we will analyze the given equations and derive the necessary relationships. ### Step 1: Write the equations of the circle and the line The equations given are: 1. Circle: \( x^2 + y^2 = a^2 \) 2. Line: \( y = mx + c \) ### Step 2: Substitute the line equation into the circle equation Substituting \( y = mx + c \) into the circle equation: \[ x^2 + (mx + c)^2 = a^2 \] Expanding the equation: \[ x^2 + (m^2x^2 + 2mcx + c^2) = a^2 \] This simplifies to: \[ (1 + m^2)x^2 + 2mcx + (c^2 - a^2) = 0 \] This is a quadratic equation in \( x \). ### Step 3: Identify coefficients for the quadratic equation From the quadratic equation \( Ax^2 + Bx + C = 0 \), we identify: - \( A = 1 + m^2 \) - \( B = 2mc \) - \( C = c^2 - a^2 \) ### Step 4: Use the properties of the roots Let \( x_1 \) and \( x_2 \) be the roots of the quadratic equation. According to Vieta's formulas: - Sum of the roots: \( x_1 + x_2 = -\frac{B}{A} = -\frac{2mc}{1 + m^2} \) - Product of the roots: \( x_1 x_2 = \frac{C}{A} = \frac{c^2 - a^2}{1 + m^2} \) ### Step 5: Calculate the length of the chord The length of the chord can be calculated using the formula: \[ \text{Length of chord} = \sqrt{(x_1 - x_2)^2 + (y_1 - y_2)^2} \] Since \( y_1 = mx_1 + c \) and \( y_2 = mx_2 + c \), we have: \[ y_1 - y_2 = m(x_1 - x_2) \] Thus, the length of the chord becomes: \[ \sqrt{(x_1 - x_2)^2 + (m(x_1 - x_2))^2} = \sqrt{(1 + m^2)(x_1 - x_2)^2} \] ### Step 6: Relate the length of the chord to the given length \( 2b \) Given that the length of the chord is \( 2b \): \[ \sqrt{(1 + m^2)(x_1 - x_2)^2} = 2b \] Squaring both sides: \[ (1 + m^2)(x_1 - x_2)^2 = 4b^2 \] ### Step 7: Calculate \( (x_1 - x_2)^2 \) From Vieta's formulas, we know: \[ x_1 - x_2 = \sqrt{(x_1 + x_2)^2 - 4x_1x_2} \] Substituting the values: \[ (x_1 - x_2)^2 = \left(-\frac{2mc}{1 + m^2}\right)^2 - 4\left(\frac{c^2 - a^2}{1 + m^2}\right) \] This leads to: \[ (x_1 - x_2)^2 = \frac{4m^2c^2}{(1 + m^2)^2} - \frac{4(c^2 - a^2)}{1 + m^2} \] ### Step 8: Substitute into the chord length equation Substituting this expression back into the chord length equation: \[ (1 + m^2)\left(\frac{4m^2c^2}{(1 + m^2)^2} - \frac{4(c^2 - a^2)}{1 + m^2}\right) = 4b^2 \] This simplifies to: \[ 4m^2c^2 - 4(c^2 - a^2)(1 + m^2) = 4b^2 \] ### Step 9: Final equation Rearranging gives us the final equation: \[ m^2c^2 - b^2 - c^2 + a^2 + a^2m^2 = 0 \]
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OBJECTIVE RD SHARMA ENGLISH-CIRCLES-Exercise
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  3. If the circle x^2 + y^2 = a^2 cuts off a chord of length 2b from the l...

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  4. The area of the circle centred at (1,2) and passing through the point ...

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  5. For the equation ax^(2) +by^(2) + 2hxy + 2gx + 2fy + c =0 where a n...

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  6. The equation of the circle passing through (4, 5) having the centre (2...

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  7. The locus of the centre of a circle of radius 2 which rolls on the out...

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  8. Find the values of k for which the points (2k ,3k),(1,0),(0,1),a n d(0...

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  9. A square is inscribed in the circle x^2+y^2-2x+4y-93=0 with its sides ...

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  11. The equation of circles passing through (3, -6) touching both the axes...

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  12. The centre of a circle passing through (0,0), (1,0) and touching the C...

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  13. If 2x-4y=9 and 6x-12y+7=0 are parallel tangents to circle, then radiu...

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  14. Equation of the diameter of the circle is given by x^(2)+y^(2)-12x+4+6...

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  15. The length of the chrod cut-off by y=2x+1 from the circle x^(2)+y^(2)=...

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  16. Area of a circle in which a chord of length sqrt2 makes an angle (pi)/...

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  17. The coordinates of the middle point of the chord cut-off by 2x-5y+18=0...

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  18. Find the equation of the circle passing through the points (1,-2)a ...

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  20. Equation of the circle with centre on the Y-axis and passing through t...

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