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Let z(0) be the circumcenter of an equil...

Let `z_(0)` be the circumcenter of an equilateral triangle whose affixes are `z_(1),z_(2),z_(3)`.
Statement-1 : `z_(1)^(2)+z_(2)^(2)+z_(3)^(2)=3z_(0)^(2)`
Statement-2: `z_(1)^(2)+z_(2)^(2)+z_(3)^(2)=2(z_(1)z_(2)+z_(2)z_(3)+z_(3)z_(1))`

A

Statement-1 is True, Statement-2 is True: Statement-2 is a correct exp,anation for statement-1.

B

Statement-1 is true, statement -2 is true, Statement-2 is not a correct explanation for statement-1.

C

Statement-1 is True, statement-2 is false,

D

statement-1 is False, Statement-2 is true.

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem, we need to analyze the two statements regarding the circumcenter \( z_0 \) of an equilateral triangle with affixes \( z_1, z_2, z_3 \). ### Step 1: Understanding the circumcenter of an equilateral triangle The circumcenter \( z_0 \) of an equilateral triangle is the same as its centroid. Therefore, we can express \( z_0 \) as: \[ z_0 = \frac{z_1 + z_2 + z_3}{3} \] ### Step 2: Analyzing Statement 1 We need to verify the statement: \[ z_1^2 + z_2^2 + z_3^2 = 3z_0^2 \] Substituting \( z_0 \): \[ z_0^2 = \left(\frac{z_1 + z_2 + z_3}{3}\right)^2 = \frac{(z_1 + z_2 + z_3)^2}{9} \] Using the identity \( (a + b + c)^2 = a^2 + b^2 + c^2 + 2(ab + bc + ca) \): \[ (z_1 + z_2 + z_3)^2 = z_1^2 + z_2^2 + z_3^2 + 2(z_1z_2 + z_2z_3 + z_3z_1) \] Substituting this back: \[ z_0^2 = \frac{z_1^2 + z_2^2 + z_3^2 + 2(z_1z_2 + z_2z_3 + z_3z_1)}{9} \] Thus, \[ 3z_0^2 = \frac{1}{3}(z_1^2 + z_2^2 + z_3^2 + 2(z_1z_2 + z_2z_3 + z_3z_1)) \] Multiplying through by 3 gives: \[ 9z_0^2 = z_1^2 + z_2^2 + z_3^2 + 2(z_1z_2 + z_2z_3 + z_3z_1) \] This simplifies to: \[ z_1^2 + z_2^2 + z_3^2 = 3z_0^2 \] So, **Statement 1 is true**. ### Step 3: Analyzing Statement 2 We need to verify the statement: \[ z_1^2 + z_2^2 + z_3^2 = 2(z_1z_2 + z_2z_3 + z_3z_1) \] From our previous derivation, we found: \[ z_1^2 + z_2^2 + z_3^2 = z_1z_2 + z_2z_3 + z_3z_1 \] This implies that: \[ z_1^2 + z_2^2 + z_3^2 \neq 2(z_1z_2 + z_2z_3 + z_3z_1) \] Thus, **Statement 2 is false**. ### Conclusion - **Statement 1 is true**: \( z_1^2 + z_2^2 + z_3^2 = 3z_0^2 \) - **Statement 2 is false**: \( z_1^2 + z_2^2 + z_3^2 \neq 2(z_1z_2 + z_2z_3 + z_3z_1) \)
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