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The inequality |z-4| < |z-2| represents...

The inequality `|z-4| < |z-2|` represents

A

Re(z) `lt 0`

B

Re(z) `gt 0`

C

Re(z) `gt 2`

D

Re(z) `gt 3`

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To solve the inequality \( |z - 4| < |z - 2| \), we will follow these steps: ### Step 1: Rewrite the inequality We start with the given inequality: \[ |z - 4| < |z - 2| \] ### Step 2: Interpret the inequality geometrically The expression \( |z - 4| \) represents the distance from the complex number \( z \) to the point \( 4 + 0i \) (which is the point \( (4, 0) \) on the Argand plane), and \( |z - 2| \) represents the distance from \( z \) to the point \( 2 + 0i \) (the point \( (2, 0) \)). ### Step 3: Identify the points on the Argand plane We plot the points \( (4, 0) \) and \( (2, 0) \) on the Argand plane. The inequality states that the distance from \( z \) to \( (4, 0) \) must be less than the distance from \( z \) to \( (2, 0) \). ### Step 4: Find the midpoint The midpoint between the points \( (4, 0) \) and \( (2, 0) \) is: \[ \left( \frac{4 + 2}{2}, 0 \right) = (3, 0) \] This means that the line \( x = 3 \) (where the real part of \( z \) is 3) bisects the segment between these two points. ### Step 5: Determine the region Since we want the distance to \( (4, 0) \) to be less than the distance to \( (2, 0) \), the region satisfying this inequality will be to the left of the line \( x = 3 \). Thus, we can express this condition as: \[ \text{Re}(z) < 3 \] ### Step 6: Conclusion The inequality \( |z - 4| < |z - 2| \) represents the region in the complex plane where the real part of \( z \) is less than 3. ### Final Result The solution can be summarized as: \[ \text{The region represented by } |z - 4| < |z - 2| \text{ is } \text{Re}(z) < 3. \] ---
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OBJECTIVE RD SHARMA ENGLISH-COMPLEX NUMBERS -Exercise
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  4. Find the number of non-zero integral solutions of the equation |1-i|^(...

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  5. If "Im"(2z+1)/(iz+1)=-2, then locus of z, is

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  6. about to only mathematics

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  7. If x=-5+2sqrt(-4) , find the value of x^4+9x^3+35 x^2-x+4.

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  8. If z(1),z(2), z(3) are vertices of an equilateral triangle with z(0) i...

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  9. If z(1) , z(2) are two complex numbers such that I m (z(1) + z(2)) = 0...

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  10. If z^2+z|z|+|z^2|=0, then the locus z is a. a circle b. a straight ...

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  11. If log(sqrt3) ((|z|^(2)-|z|+1)/(2+|z|)) lt 2 ,then the locus of z is

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  12. Let g(x) and h(x) are two polynomials such that the polynomial P(x) =g...

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  13. If g(x) and h(x) are two polynomials such that the polynomials P(x)=g(...

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  16. If (a(1)+ib(1))(a(2)+ib(2))………………(a(n)+ib(n))=A+iB, then sum(i=1)^(n) ...

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  18. If alpha,betaandgamma are the cube roots of P(p)lt0), then for any x, ...

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