If (a1+ib1)(a2+ib2).....(an+ibn)=A+iB, t...

If `(a_1+ib_1)(a_2+ib_2).....(a_n+ib_n)=A+iB`, then `(a_1^2+b_1^2)(a_2^2+b_2^2)......(a_n^2+b_n^2)` is equal to (A) 1 (B) `(A^2+B^2)` (C) `(A+B)` (D) `(1/A^2+1/B^2)`

A

1

B

`A^(2)+B^(2)`

C

`A+B`

D

`1/A^(2)+1/B^(2)`

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The correct Answer is:

b

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