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A

`P sub Q and Q-P=phi`

B

`Q cancelsub P`

C

`B cap C`

D

`A cap B capC`

Text Solution

Verified by Experts

`theta in P`
`hArr sin theta - cos theta = sqrt(2)cos theta`
`hArr ( sin theta - cos theta)^(2)= 2cos ^(2)theta`
`hArr sin ^(2) theta + cos ^(2) theta - 2 sin theta -2 sin theta cos theta = 2 cos^(2)theta `
`hArr cos^(2) theta + 2 sin theta cos theta + sin ^(2) theta = 2 sin^(2) theta `
`hArr (cos theta + sin theta)^(2)= 2 sin ^(2) theta `
`hArr cos theta + sin theta = sqrt(2) sin theta`
`hArr theta in Q`.
hence P=Q.
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