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in a class of 45 student, 22 can spea...

in a class of 45 student, 22 can speak hindi and 12 can speak English only . The number of students , who can speak both Hindi and English , is

A

9

B

11

C

23

D

17

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The correct Answer is:
To solve the problem step by step, we can use the principle of inclusion-exclusion for sets. ### Step 1: Define the variables Let: - \( N_H \) = Number of students who can speak Hindi = 22 - \( N_E \) = Number of students who can speak English = 12 (only English) - \( X \) = Number of students who can speak both Hindi and English ### Step 2: Write down the total number of students We know the total number of students in the class is 45. Therefore, we can express this as: \[ N_H \cup N_E = 45 \] ### Step 3: Express the total number of students in terms of \( X \) According to the principle of inclusion-exclusion: \[ N_H \cup N_E = N_H + N_E - N_H \cap N_E \] Where \( N_H \cap N_E \) is the number of students who can speak both languages, which we have defined as \( X \). Substituting the values we have: \[ 45 = (22 + X) + (12 + X) - X \] ### Step 4: Simplify the equation Now, simplify the equation: \[ 45 = 22 + X + 12 + X - X \] \[ 45 = 22 + 12 + X \] \[ 45 = 34 + X \] ### Step 5: Solve for \( X \) Now, isolate \( X \): \[ X = 45 - 34 \] \[ X = 11 \] ### Conclusion The number of students who can speak both Hindi and English is \( \boxed{11} \). ---
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OBJECTIVE RD SHARMA ENGLISH-SETS-Exercise
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  7. If A ={ theta : 2cos^2 theta + sintheta <=2} , and B = {theta: pi/2<=t...

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  9. If A and B are two given sets, then Ann(AnnB)^(@) is equal to :

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  10. Let n(U)=700, n(A)=200,n(B)=300 and n(AnnB)=100, then find n(A'nnB')

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  13. In a city 20% of the population travels by car, 50% by bus and 10% tra...

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  15. Two finite sets have m and n elements respectively . The total number ...

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  16. In a class of 175 students the following data shows the number of stu...

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