Statement-1: In any `DeltaABC` if A is obtuse, then tanBtanC`lt1`
Statement-2: In any `!ABC`, we have
tan A + tan B + tan C = tan A tan B tan C

Options

A. Statement-1 is True, Statement-2 is true, Statement-2 is a correct explanation for Statement-1.
B. Statement-1 is True, Statement-2 is True, Statement-2 is not a correct explanation for Statement-1.
C. Statement-1 is True, Statement-2 is False.
D. Statement-1 is False, Statement- 2 is True.

Explanation

To solve the given problem, we need to analyze both statements provided and determine their truth values and relationships.

### Step 1: Analyze Statement 1
**Statement 1:** In any triangle \( \Delta ABC \), if angle \( A \) is obtuse, then \( \tan B \tan C < 1 \).

1. Since \( A \) is obtuse, we know that \( A > 90^\circ \).
2. Therefore, the sum of angles \( B + C = 180^\circ - A \) is acute (since \( A < 180^\circ \)).
3. We can express \( B + C \) as \( B + C = 180^\circ - A \).