In `!ABC` it is given that a:b:c = cos A:cos B:cos C
Statement-1: `!ABC` is equilateral.
Statement-2: cosA`=(b^(2)+c^(2)-a^(2))/(2bc),cosB=(c^(2)+a^(2)-b^(2))/(2ac),cosC=(a^(2)+b^(2)-c^(2))/(2ab)`

Options

A. Statement-1 is True, Statement-2 is true, Statement-2 is a correct explanation for Statement-1.
B. Statement-1 is True, Statement-2 is True, Statement-2 is not a correct explanation for Statement-1.
C. Statement-1 is True, Statement-2 is False.
D. Statement-1 is False, Statement- 2 is True.

Explanation

To solve the problem, we need to analyze the statements given about triangle \(ABC\) and the relationship between the sides and the cosines of the angles.

### Step-by-Step Solution:

1. **Understanding the given ratio**:
We are given that \( a:b:c = \cos A:\cos B:\cos C \). This implies that:
\[
\frac{a}{\cos A} = \frac{b}{\cos B} = \frac{c}{\cos C}
...