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In a triangleABC,B=pi/8, C=(5pi)/(8). Th...

In a `triangleABC,B=pi/8, C=(5pi)/(8)`. The altitude from A to the side BC, is

A

`a/2`

B

2a

C

`1/2(b+c)`

D

b+c

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The correct Answer is:
To find the altitude from vertex A to side BC in triangle ABC, where \( B = \frac{\pi}{8} \) and \( C = \frac{5\pi}{8} \), we will use the formula for the altitude from a vertex in a triangle. ### Step-by-Step Solution: 1. **Identify the Angles**: - Given \( B = \frac{\pi}{8} \) and \( C = \frac{5\pi}{8} \). - To find angle \( A \), use the fact that the sum of angles in a triangle is \( \pi \): \[ A = \pi - B - C = \pi - \frac{\pi}{8} - \frac{5\pi}{8} = \pi - \frac{6\pi}{8} = \frac{2\pi}{8} = \frac{\pi}{4} \] 2. **Use the Altitude Formula**: - The formula for the altitude \( h_A \) from vertex A to side BC is given by: \[ h_A = \frac{a}{\cot A + \cot B + \cot C} \] - We need to find \( \cot A \), \( \cot B \), and \( \cot C \). 3. **Calculate Cotangents**: - Calculate \( \cot A \): \[ \cot A = \cot \left(\frac{\pi}{4}\right) = 1 \] - Calculate \( \cot B \): \[ \cot B = \cot \left(\frac{\pi}{8}\right) = \frac{\cos \frac{\pi}{8}}{\sin \frac{\pi}{8}} \] - Calculate \( \cot C \): \[ \cot C = \cot \left(\frac{5\pi}{8}\right) = \frac{\cos \frac{5\pi}{8}}{\sin \frac{5\pi}{8}} = -\cot \left(\frac{3\pi}{8}\right) = -\frac{\cos \frac{3\pi}{8}}{\sin \frac{3\pi}{8}} \] 4. **Use Cotangent Addition**: - We can use the identity for cotangent: \[ \cot B + \cot C = \cot \left(\frac{\pi}{8}\right) - \cot \left(\frac{3\pi}{8}\right) \] - This can be simplified further using known values or identities. 5. **Combine Cotangents**: - Now, substitute back into the altitude formula: \[ h_A = \frac{a}{\cot \left(\frac{\pi}{4}\right) + \cot \left(\frac{\pi}{8}\right) + \cot \left(\frac{5\pi}{8}\right)} \] - This will yield a numerical value once \( a \) is known. 6. **Final Calculation**: - If we assume \( a = 2 \) (for simplicity), then: \[ h_A = \frac{2}{1 + \cot \left(\frac{\pi}{8}\right) - \cot \left(\frac{3\pi}{8}\right)} \] - After evaluating the cotangent values, we can find the altitude. ### Conclusion: The altitude from A to side BC can be expressed as: \[ h_A = \frac{a}{\cot B + \cot C + 1} \] For specific values of \( a \), the altitude can be calculated numerically.
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OBJECTIVE RD SHARMA ENGLISH-PROPERTIES OF TRIANGLES AND CIRCLES CONNECTED WITH THEM-Chapter Test
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