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4/5 of 5 kg apples were used on Monday. ...

`4/5` of 5 kg apples were used on Monday. The next day `1/3` of what was left was used. Weight (in kg) of apples left now is:

A

`2/7`

B

`1/14`

C

`2/3`

D

`4/21`

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem step-by-step, we will follow the instructions given in the question: ### Step 1: Calculate the amount of apples used on Monday. We know that `4/5` of `5 kg` apples were used on Monday. To find out how much was used: \[ \text{Apples used on Monday} = \frac{4}{5} \times 5 \text{ kg} \] Calculating this gives: \[ \frac{4 \times 5}{5} = 4 \text{ kg} \] ### Step 2: Calculate the amount of apples left after Monday. Initially, there were `5 kg` of apples. After using `4 kg` on Monday, the remaining apples are: \[ \text{Apples left} = 5 \text{ kg} - 4 \text{ kg} = 1 \text{ kg} \] ### Step 3: Calculate the amount of apples used on Tuesday. On Tuesday, `1/3` of the remaining apples (which is `1 kg`) were used. To find out how much was used: \[ \text{Apples used on Tuesday} = \frac{1}{3} \times 1 \text{ kg} \] Calculating this gives: \[ \frac{1}{3} \text{ kg} \] ### Step 4: Calculate the weight of apples remaining after Tuesday. Now, we need to find out how many apples are left after using `1/3 kg` on Tuesday. We have `1 kg` left after Monday, and we used `1/3 kg` on Tuesday: \[ \text{Apples remaining} = 1 \text{ kg} - \frac{1}{3} \text{ kg} \] To perform this subtraction, we can convert `1 kg` into a fraction with a common denominator: \[ 1 \text{ kg} = \frac{3}{3} \text{ kg} \] Now, we can subtract: \[ \text{Apples remaining} = \frac{3}{3} \text{ kg} - \frac{1}{3} \text{ kg} = \frac{2}{3} \text{ kg} \] ### Final Answer: The weight of apples left now is \(\frac{2}{3} \text{ kg}\). ---
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